Question

What is the distance between (8, -3) and (4, - 7)?

Answer 1

Answer:

$distance=\sqrt{32}$  , which agrees with answer "c" in your list of possible options

Step-by-step explanation:

Use the formula for distance between two points $(x_1,y_1)$, and $(x_2,y_2)$ on the plane:

$distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\distance= \sqrt{(4-8)^2+(-7-(-3))^2} \\distance= \sqrt{(-4)^2+(-4)^2} \\distance=\sqrt{16+16}\\distance=\sqrt{32}$