Answer:
RTA= (x-2)·(x-11/2)/(x-2)(x-4)= (you can simplify again if you want by eliminating both (x-2)
(x-11/2)/(x-4)
Step-by-step explanation:
Ok we need to simplify the expression so:
x^2+3x-10= Bhaskara formula=
-3(±√9-4·1·(-10))/2·1=
X1=(-3+7/2)--> X1=2(R)---> (X-R)--->X-2
X2=(-3-7)/2 --> X2=11/2(R)---> (X-R)--->X-11/2
x^2-6x+8= Bhaskara formula=
6(±√36-4·1·8)/2·1=
X1=(6-2)/2=2--> X1=2(R)---> (X-R)--->X-2
X2=(6+2)/2=2--> X2=4(R)---> (X-R)--->X-4
so, The simplify expression is
(x-2)·(x-11/2)/(x-2)(x-4)=
Answer:
x = -13
Step-by-step explanation:
9 - 2x = 35
Subtract 9 from both sides of the equation:
9 - 2x - 9 = 35 - 9
-2x = 26
Divide both sides of the equation by -2:
x= -13
Answer:
47xy
Step-by-step explanation:
The answer is 47xy because you add the area of the first quadrant to the second quadratic triangle to reactive the triangle bade
The value of x when f(x) = -4 is 3
<h3>How to solve the function?</h3>
The function is given as:
f(x) = -3x + 5
When f(x) = -4, we have:
-4 = -3x + 5
Subtract 5 from both sides
-3x = -9
Divide both sides by -3
x = 3
Hence, the value of x when f(x) = -4 is 3
Read more about functions at:
brainly.com/question/4025726
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5/2 is already in its simplest form. You cannot reduce this fraction any further.
