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Makovka662 [10]
3 years ago
14

Can YOU plz help meh

Mathematics
1 answer:
Aleks [24]3 years ago
7 0
8 × 20= 160; 8 × 4= 32; 160 + 32= 192; 8 × t= 192; 192 ÷ 8= 24; t=24
The answer is t = 24

Hope this helps :)
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Holden is trying to determine the velocity of his race car. He went 20 meters east, turned around, and went 40 meters west. He t
AnnyKZ [126]

Answer:

The velocity of Holden's race car is 3m/s

Step-by-step explanation:

Velocity =Displacement/Time

Displacement=Final Position - Initial Position

Now, although e went 20 meters east, turned around, and went 40 meters west. He also turned the car one more time and went 35 meters east.

We are not looking for the distance travelled, we only require his displacement.

Holden's car is 15 metres from his starting line, so his displacement =15m

Time taken =5 seconds

Velocity of the Race Car

=15/5 = 3m/s

5 0
3 years ago
What does this equal?
REY [17]
Answer: No solution? Maybe I’m unsure now :/
8 0
3 years ago
First derivative of <br>√{cosec2x).show with full step.​
Mice21 [21]

Answer:

- \sf \displaystyle \:   \frac{ \cos(2x) }{ \sin ^{2} (2x)\sqrt{ \csc(2x) } }

Step-by-step explanation:

we are given a derivative

\displaystyle \:  \frac{d}{dx} ( \sqrt{  \csc(2x) } )

and said to figure out the first derivative

to do so

recall chain rule:

\sf\displaystyle \:  \frac{d}{dx} (f(g(x)) =  \frac{d}{dg} (f(g(x)) \times  \frac{d}{dx} (g)

so we get

\displaystyle \: g(x) =  \csc(2x)

rewrite the derivative using the chain rule:

\displaystyle \:  \frac{d}{dg} ( \sqrt{  g } )  \times  \frac{d}{dx} ( \csc(2x) )

use square root derivative rule to simplify:

\displaystyle \:   \frac{1}{ 2\sqrt{g} }  \times  \frac{d}{dx} ( \csc(2x) )

now we need to again use chain rule composite function derivative to simplify

where we'll take a new function n so we won't mess up two g's and we'll take 2x as n

use composite function derivative to simplify:

\sf \displaystyle \:   \frac{1}{ 2\sqrt{g} }  \times  \frac{d}{dn}( \csc(n) ) \times  \frac{d}{dx} (2x)

use derivative formula to simplify derivatives:

\sf \displaystyle \:   \frac{1}{ 2\sqrt{g} }  \times   - \cot(n)   \csc(n)  \times  2

substitute the value of n:

\sf \displaystyle \:   \frac{1}{ 2\sqrt{g} }  \times   - 2\cot(2x)   \csc(2x)

substitute the value of g:

\sf \displaystyle \:   \frac{1}{ 2\sqrt{ \csc(2x) } }  \times   - 2\cot(2x)   \csc(2x)

now we need our trigonometric skills to simplify

rewrite cot and csc:

\sf \displaystyle \:   \frac{1}{ 2\sqrt{ \csc(2x) } }  \times   - 2 \dfrac{ \cos(2x) }{ \sin(2x) }   \dfrac{1}{ \sin(2x) }

simplify multiplication:

\sf \displaystyle \:   \frac{1}{ \cancel{ \:  2}\sqrt{ \csc(2x) } }  \times    \cancel{- 2} \dfrac{ \cos(2x) }{ \sin ^{2} (2x) }

simplify multiplication:

- \sf \displaystyle \:   \frac{ \cos(2x) }{ \sin ^{2} (2x)\sqrt{ \csc(2x) } }

4 0
3 years ago
Read 2 more answers
Find the area of the triangle (-2,2) ,(2,4) and (2,5)
nikdorinn [45]
Check the picture below.

recall that the area of a triangle is (1/2)bh.

5 0
4 years ago
Find the measure of each unknown angle​
Aleks [24]
. The sum of angels in the triangle must be 180
Therefore
1) 180 - (40+85)= 55
2)180-(14+30)= 136
3 0
3 years ago
Read 2 more answers
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