3 years ago

Solve 2^(3x-4)=5 round to the nearest ten-thousandth

Mathematics

1 answer:

Inga [223]3 years ago

5 0

The answer is 345 because you have to round

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Decompose the following 3 2/5

quester [9]

Decompose the following 3 2/5

$3 \dfrac{2}{5} = \dfrac{3*5}{5}+ \dfrac{2}{5} = \dfrac{15}{5}+ \dfrac{2}{5} = \boxed{ \frac{17}{5}} \\ \\ \\ The \ answer\ is\to \boxed{3 \dfrac{2}{5} =\frac{17}{5}}$

I wish you much success in your studies!!!!

4 0

3 years ago

(9+7i)+(-5-31) =<br> add complex numbers

ra1l [238]

Answer:

4 + 4i

Step-by-step explanation:

Add the real part and add the imaginary part.

9 + 7i + (-5 - 3i) = 9 + 7i - 5 - 3i

= 9 - 5 + 7i - 3i

= 4 + 4i

7 0