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Sloan [31]
3 years ago
8

Can someone hlpe with questions A and/or B please

Mathematics
1 answer:
pickupchik [31]3 years ago
5 0
Let sample in Texas be p1, Louisiana be p2.
Null Hypothesis: 
p1 - p2 = 0
Alternative Hypothesis: (This represents the claim)
p1- p2 < 0

To calculate test statistic, you need the pooled estimate which is a weighted average of the 2 sample proportions.
P = \frac{n_1 p_1 + n_2 p_2}{n_1 + n_2} = \frac{2000(.179+.265)}{2000+2000} = 0.222
Next get standard error:
SE = \sqrt{P(1-P)(\frac{1}{n_1} + \frac{1}{n_2})} = \sqrt{.222(1-.222)(\frac{1}{2000}+\frac{1}{2000})} = 0.01314
Calculate test statistic:
Z = \frac{p_1 - p_2}{SE} = \frac{.179 - .256}{.01314} = -5.86
To find p-value, look up Z-value in standard normal table.
Anything smaller than -3 or larger than 3, you can estimate to have
p-value = 0.

If p-value < alpha, Reject Null Hypothesis.
For this example, 0 < 0.05, therefore reject null hypothesis.

There is evidence to support claim that proportion of smokers in Texas is LESS than Louisiana.
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Answer:

The Value of a=\frac{15}{4}.

Step-by-step explanation:

We have Named the figure please find the attachment for your reference.

Given:

PR = y

QR = a

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PS = z

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QS = 15

∠P = 90°

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∠Q = 60°

∠S = 30°

We need to find the Value of 'a'.

Solution:

Now we know that:

In Δ PQS

∠P = 90°

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Now we know that;

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Substituting the given values we get;

sin\ 30\°=\frac{x}{15}

Now we know that;

sin\ 30\° = \frac12

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Now In Triangle PQR.

∠R = 90°

∠Q = 60°

So we can say that;

Cos \theta = \frac{adjacent \ Side}{Hypotenuse}\\

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Substituting the given values we get;

cos 60\°= \frac{a}{x}

Now we know that;

cos 60\°= \frac12

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So substituting the values we get;

\frac{1}{2}=\frac{a}{\frac{15}{2}}

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a= \frac{1}{2}\times\frac{15}{2}\\\\a=\frac{15}{4}

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