Answer:
Step-by-step explanation:
The altitude to the hypotenuse of a right triangle create two smaller triangles, all of which are similar to the original. This means corresponding sides are proportional.
3. Using the above relationship, ...
short-side/hypotenuse = 8/y = y/(8+23)
y^2 = 8·31
y = 2√62
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long-side/hypotenuse = z/(8+23) = 23/z
z^2 = 23·31
z = √713
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short-side/long-side = 8/x = x/23
x^2 = 8·23
x = 2√46
_____
4. The picture is fuzzy, but we think the lengths are 25 and 5. If they're something else, use the appropriate numbers. Using the same relations we used for problem 3,
y = √(5·25) = 5√5 . . . . . . . = √(short segment × hypotenuse)
z = √(20·25) = 10√5 . . . . . = √(long segment × hypotenuse)
x = √(5·20) = 10 . . . . . . . . . = √(short segment × long segment)
Answer:
Let x be the number of employees
50x
Step-by-step explanation:
Answer:
The first one
Step-by-step explanation:
To figure out which one is the best deal, for each one how much <em>one</em> t-shirt costs.
<u>First deal:</u>
3 t-shirts for $28.95
To figure out how much money one t-shirt would cost, you divide $28.95 by 3.
1 t-shirt = 28.95/3 = $9.65.
<u>Second deal:</u>
4 t-shirts for $39
Same thing as the last one, except since there are 4 t-shirts you divide $39 by 4.
1 t-shirt = 39/4 = $9.75
<u>Third deal:</u>
5 t-shirts for $49.95
This time you will divide 49.95 by 5.
1 t-shirt = 49.95/5 = $9.99
The last step is to compare the three deals, and since you are trying to find the one that costs the <em>least</em> you can see that the first deal is the best one, because $9.65 per shirt is cheaper than $9.75 and $9.99
Answer:
Step-by-step explanation:
f(x)=2(x+4)(x-1)
=(2x+8)(x-1)
<h3>=2x²-2x+8x-8</h3>
=2x²+6x-8
Answer: x=1.5811389999999999 , or 1.59
Step-by-step explanation:
First, Subtract 20 from both sides.
12x2+20−20=50−20
12x2=30
Then, Divide both sides by 12:
12x^2/12 = 30/12
⇒ you get : x^2 = 5/2
After, Take square root.
x= ± √ 5/2
Finally you answer is going to be =1.5811389999999999 OR, 1.59
* Hopefully this helps:) Mark me the brainliest:)
<em>∞ 234483279c20∞</em>
