3 years ago

The sum of three different positive integers is 12. show that one of them must be greater than 4.

2 answers:

4 0

Let n = 1st positive interger
n+1 = 2nd
n + 2 = 3rd

n+n+1+n+2 = 12
3n + 3 = 12
Minus 3 from 3 and 12

3n = 9
Divide 3n and 9 by 3

n = 3
So, the three intergers are 3, 4, and 5.

Blababa [14]3 years ago

3 0

If one is 4 , then other may be 3 and so other 2......this will get you only 9 .

so it is understood that one must be greater than 4

You might be interested in

A system of two linear equations in which the lines are identical is classified as __________.

Luba_88 [7]

Answer:

Step-by-step explanation:

c. consistent and dependent

3 0

3 years ago

Read 2 more answers

triangle P is similar to triangle Q. triangle P has two angle with measures of 41degress and 82 degrees. which two angle measure

Sliva [168]

Since they are similar, they have equal angles which means the angles of Q are 57, 41, and 82

7 0

3 years ago

How do you add/subtract radical operations? I know how to simply and stuff, but how do you do things like 4 square root of 2 plu

LuckyWell [14K]

U get a calculator and u put 4^2+7^4 n u put it in the calculator but the pic shows what a sqaure root looks like n u see the button with the x2 u can press that for when u put the 4 square root 2 then plus 7 n then u hit the button that has this symbol ^ n hit 4 then equal an itll give u the answer which is 2417.