Ok start off by finding the base first and the equation of finding the area of the square is A=bh
A=11 x 11= 121 cm^2
Next find the area of one triangle and the equation is A=1/2bh
A=1/2(11)(10)
A=55 cm^2
Multiply the area of one triangle by 4 since there are four triangles and it should equal to 220 cm^2. You then add this to the base and the final answer should be 341 cm^2.
I hope this helps
Answer: Because
Step-by-step explanation: Yeah im good
I hope this helps you
72/75=0.96
Solution :
Along the edge 
The parametric equation for is given :
Along edge 
The curve here is a quarter circle with the radius 9. Therefore, the parametric equation with the domain 
is then given by :
Along edge 
The parametric equation for is :
Now,
x = 9t, ⇒ dx = 9 dt
y = 0, ⇒ dy = 0
And
Then :
![$=\int_0^1 \left[\left( 9 \sin \frac{\pi}{2}t\right)^2\left(9 \cos \frac{\pi}{2}t\right)\left(-\frac{7 \pi}{2} \sin \frac{\pi}{2}t dt\right) + \left( 9 \cos \frac{\pi}{2}t\right)^2\left(9 \sin \frac{\pi}{2}t\right)\left(\frac{7 \pi}{2} \cos \frac{\pi}{2}t dt\right) \right]$](https://tex.z-dn.net/?f=%24%3D%5Cint_0%5E1%20%5Cleft%5B%5Cleft%28%209%20%5Csin%20%5Cfrac%7B%5Cpi%7D%7B2%7Dt%5Cright%29%5E2%5Cleft%289%20%5Ccos%20%5Cfrac%7B%5Cpi%7D%7B2%7Dt%5Cright%29%5Cleft%28-%5Cfrac%7B7%20%5Cpi%7D%7B2%7D%20%5Csin%20%5Cfrac%7B%5Cpi%7D%7B2%7Dt%20dt%5Cright%29%20%2B%20%5Cleft%28%209%20%5Ccos%20%5Cfrac%7B%5Cpi%7D%7B2%7Dt%5Cright%29%5E2%5Cleft%289%20%5Csin%20%5Cfrac%7B%5Cpi%7D%7B2%7Dt%5Cright%29%5Cleft%28%5Cfrac%7B7%20%5Cpi%7D%7B2%7D%20%5Ccos%20%5Cfrac%7B%5Cpi%7D%7B2%7Dt%20dt%5Cright%29%20%5Cright%5D%24)
![$=\left[-9^4\ \frac{\cos^4\left(\frac{\pi}{2}t\right)}{\frac{\pi}{2}} -9^4\ \frac{\sin^4\left(\frac{\pi}{2}t\right)}{\frac{\pi}{2}} \right]_0^1$](https://tex.z-dn.net/?f=%24%3D%5Cleft%5B-9%5E4%5C%20%5Cfrac%7B%5Ccos%5E4%5Cleft%28%5Cfrac%7B%5Cpi%7D%7B2%7Dt%5Cright%29%7D%7B%5Cfrac%7B%5Cpi%7D%7B2%7D%7D%20-9%5E4%5C%20%5Cfrac%7B%5Csin%5E4%5Cleft%28%5Cfrac%7B%5Cpi%7D%7B2%7Dt%5Cright%29%7D%7B%5Cfrac%7B%5Cpi%7D%7B2%7D%7D%20%5Cright%5D_0%5E1%24)
= 0
And
x = 0, ⇒ dx = 0
y = 9 t, ⇒ dy = 9 dt
Therefore,
= 0 + 0 + 0
Applying the Green's theorem
Here,
Therefore,
The vector field F is = 
is conservative.
Answer:
The account statement had an ending balance of $153
Step-by-step explanation:
Check register actual balance= $256
Less; Written check= -$312
The account is short; $256-$312= -$56
Add the new deposit =-$56+$250= $194
Therefore , new account balance= $194
Subtract fees($8 & $33) from the balance= $194- $8- $33=$153
The account statement had an ending balance of $153
