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2 years ago

9

Find cos(β) in the triangle.

1 answer:

svetlana [45]2 years ago

8 0

90°+b+b =180

90°+ 2b=180

2b=180-90

2b= 90

<u>2</u><u>b</u><u>=</u><u>9</u><u>0</u>

<u>2</u> = 2

b=45°

ave tried I don't know if its correct

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12. Jeremy has $10.00 in quarters to spend on candy. What

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Answer:

Step-by-step explanation:

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3 years ago

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Which angles are supplementary to each other? Select all that apply.

Orlov [11]

Supplementary angles are angles that together, for an angle of 180°. Straight lines are also 180°, so what you need to look for in this exercise are angles, next to eachother, on the same straight line.

those are:

1,2

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so the right answers are option 1 and 2

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3 years ago

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I dont know how to do this one

-BARSIC- [3]

Answer:

$2\sqrt{34}$

Step-by-step explanation:

We can add a line to create a triangle and a rectangle. The triangle will have side lengths 10 and 6. Furthermore, it will be a right triangle, meaning we can apply the Pythagorean Theorem to find x, the hypotenuse.

$6^2 + 10^2 = x^2\\x = \sqrt{6^2 + 10^2}\\ = \sqrt{136} \\= 2\sqrt34}$

hope this helped! :)

7 0

2 years ago

If a,b,c and d are positive real numbers such that logab=8/9, logbc=-3/4, logcd=2, find the value of logd(abc)

Eva8 [605]

We can expand the logarithm of a product as a sum of logarithms:

$\log_dabc=\log_da+\log_db+\log_dc$

Then using the change of base formula, we can derive the relationship

$\log_xy=\dfrac{\ln y}{\ln x}=\dfrac1{\frac{\ln x}{\ln y}}=\dfrac1{\log_yx}$

This immediately tells us that

$\log_dc=\dfrac1{\log_cd}=\dfrac12$

Notice that none of $a,b,c,d$ can be equal to 1. This is because

$\log_1x=y\implies1^{\log_1x}=1^y\implies x=1$

for any choice of $y$ . This means we can safely do the following without worrying about division by 0.

$\log_db=\dfrac{\ln b}{\ln d}=\dfrac{\frac{\ln b}{\ln c}}{\frac{\ln d}{\ln c}}=\dfrac{\log_cb}{\log_cd}=\dfrac1{\log_bc\log_cd}$

so that

$\log_db=\dfrac1{-\frac34\cdot2}=-\dfrac23$

Similarly,

$\log_da=\dfrac{\ln a}{\ln d}=\dfrac{\frac{\ln a}{\ln b}}{\frac{\ln d}{\ln b}}=\dfrac{\log_ba}{\log_bd}=\dfrac{\log_db}{\log_ab}$

so that

$\log_da=\dfrac{-\frac23}{\frac89}=-\dfrac34$

So we end up with

$\log_dabc=-\dfrac34-\dfrac23+\dfrac12=-\dfrac{11}{12}$

###

Another way to do this:

$\log_ab=\dfrac89\implies a^{8/9}=b\implies a=b^{9/8}$

$\log_bc=-\dfrac34\implies b^{-3/4}=c\implies b=c^{-4/3}$

$\log_cd=2\implies c^2=d\implies\log_dc^2=1\implies\log_dc=\dfrac12$

Then

$abc=(c^{-4/3})^{9/8}c^{-4/3}c=c^{-11/6}$

So we have

$\log_dabc=\log_dc^{-11/6}=-\dfrac{11}6\log_dc=-\dfrac{11}6\cdot\dfrac12=-\dfrac{11}{12}$

4 0

3 years ago

PLEASE HELP I HAVE LIMITED TIME!!

MakcuM [25]

Answer:

N: n = 5 sides

side length: a = 23.2 m

inradius: r = 15.966 m

circumradius: R = 19.7351 m

Area: A = 926.03 m2

perimeter: P = 116 m

interior angle: x = 108 °

exterior angle: y = 72 °

Description:

We use the calculations on the shape 16 and 23.2. Side length is 23.2. Pi is 16. calculate the numbers and all the answers are added above.

Please mark brainliest

<em><u>Hope this helps.</u></em>

8 0

3 years ago