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Sonbull [250]
2 years ago
7

Do you have a favorite color?

Mathematics
1 answer:
Amanda [17]2 years ago
3 0

Answer:

Purple. red, blue, green, orange

You might be interested in
Help is all I need..
Solnce55 [7]

Answer:

{(x - 1)}^{2}   = 16 \\ x - 1  =  |4| \\ x  =  |4|   + 1

x = +4 +1

x = +5

and

x = -4 + 1

x = -3

7 0
3 years ago
Read 2 more answers
I’ve Tried solving this and i just can’t get it , 64 = 4 + 12g
Alika [10]

Answer:

5

Step-by-step explanation:

64 = 4 + 12g

64 - 4 = 12g

60 = 12g

60 / 12 = g

5 = g

g = 5

8 0
3 years ago
Given that f.x 3x-2 over x+1 g[x] x +5 evaluate f[-4] and gf [-2]
Jobisdone [24]

The value of f[ -4 ] and g°f[-2] are \frac{14}{3} and 13 respectively.

<h3>What is the value of f[-4] and g°f[-2]?</h3>

Given the function;

  • f(x) = \frac{3x-2}{x+1}
  • g(x)=x+5
  • f[ -4 ] = ?
  • g°f[ -2 ] = ?

For f[ -4 ], we substitute -4 for every variable x in the function.

f(x) = \frac{3x-2}{x+1}\\\\f(-4) = \frac{3(-4)-2}{(-4)+1}\\\\f(-4) = \frac{-12-2}{-4+1}\\\\f(-4) = \frac{-14}{-3}\\\\f(-4) = \frac{14}{3}

For g°f[-2]

g°f[-2] is expressed as g(f(-2))

g(\frac{3x-2}{x+1}) =  (\frac{3x-2}{x+1}) + 5\\\\g(\frac{3x-2}{x+1}) =  \frac{3x-2}{x+1} + \frac{5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{3x-2+5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{8x+3}{x+1}\\\\We\ substitute \ in \ [-2] \\\\g(\frac{3x-2}{x+1}) =  \frac{8(-2)+3}{(-2)+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{-16+3}{-2+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{-13}{-1}\\\\g(\frac{3x-2}{x+1}) =  13

Therefore, the value of f[ -4 ] and g°f[-2] are \frac{14}{3} and 13 respectively.

Learn more about composite functions here: brainly.com/question/20379727

#SPJ1

6 0
1 year ago
Are 3:5and 1:2 equivalent
german

Answer:

No. They are not equivalent.

Step-by-step explanation:

\frac{3}{5} \neq  \frac{1}{2}

=> \frac{6}{10} \neq  \frac{5}{10}

Therefore, 3/5 and 1/2 are not equivalent.

Hoped this helped.

6 0
2 years ago
Read 2 more answers
"Quadrilateral ABCD underwent a sequence of transformations to give quadrilateral A′B′C′D′. Which transformations could have tak
suter [353]
<span>The quadrilateral ABCD have vertices at points A(-6,4), B(-6,6), C(-2,6) and D(-4,4).
</span>
<span>Translating  10 units down you get points A''(-6,-6), B''(-6,-4), C''(-2,-4) and D''(-4,-6).
</span>
Translaitng <span>8 units to the right you get points A'(2,-6), B'(2,-4), C'(6,-4) and D'(4,-6) that are exactly vertices of quadrilateral A'B'C'D'.
</span><span>
</span><span>Answer: correct choice is B.
</span>

6 0
3 years ago
Read 2 more answers
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