How to solve for x where (2^x)*x =n?

1 answer:

4 0

Tough call.
You may have to use Newton's Method or something like that.
Graph y=2^x and then graph n/x on the same set of axes. You may have to assign some arbitrary value to n to make this work. From the graph you can read off the approximate coordinates of the point of intersection.

You might be interested in

What is the standard form and the factored form

Feliz [49]

Answer:

See below

Step-by-step explanation:

<u>The factored form, use variables/numbers outside the square:</u>

(x + 6)(x - 4)

<u>The standard form, use variables/numbers inside the square:</u>

x² + 6x - 4x - 24 = x² + 2x - 24

3 0

2 years ago

What should be done to x^2 + 15x in order to create a perfect square?

lana [24]

$\bf \qquad \textit{perfect square trinomial} \\\\ (a\pm b)^2\implies a^2\pm \stackrel{\stackrel{\text{\small 2}\cdot \sqrt{\textit{\small a}^2}\cdot \sqrt{\textit{\small b}^2}}{\downarrow }}{2ab} + b^2 \\\\[-0.35em] ~\dotfill$

$\bf x^2+15x+\boxed{?}^2\implies \stackrel{\textit{we know the middle term is}}{2\sqrt{x^2}\cdot \sqrt{\boxed{?}^2}\implies 2x\boxed{?}}\qquad then\qquad 2x\boxed{?}=15x \\\\\\ \boxed{?}=\cfrac{15x}{2x}\implies \boxed{?}=\cfrac{15}{2}\qquad \impliedby \textit{we should add that much \underline{squared}} \\\\[-0.35em] ~\dotfill\\\\ x^2+15x+\left( \cfrac{15}{2} \right)^2\implies \left(x+ \cfrac{15}{2} \right)^2$