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mylen [45]
3 years ago
5

How to solve for x where (2^x)*x =n?

Mathematics
1 answer:
Molodets [167]3 years ago
4 0
Tough call.  
You may have to use Newton's Method or something like that.
Graph y=2^x and then graph n/x on the same set of axes.  You may have to assign some arbitrary value to n to make this work.  From the graph you can read off the approximate coordinates of the point of intersection.
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Simplify -2/3÷ 3 3/4
Rina8888 [55]

Answer:

-8/45

Step-by-step explanation:

  1. Change 3 3/4 into an improper fraction = 4/15
  2. To change it into multiplication put the dominator on the top = -2/3 × 4/15
  3. Then multiply it.
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8 0
3 years ago
Steve is managing a skate park and has been analyzing the attendance data. Steve has found that the number of visitors increases
SashulF [63]

Answer:

Suppose that the equations are:

The number of people increases exponentially as the temperature increases, so we can write this as a simple exponential relation.

N(T) = a0*r^(T)

Also, the number of people that leaves the park as the temperature increases are:

M(T) = a*T + b

So the combination of these equations can say the number of people that are arriving to the park minus the number of people that are leaving, this would be:

N(T) - M(T) = total change in the park population as the temperature changes = C(T)

C(T) = a0*r^(T) - a*T - b

5 0
3 years ago
Read 2 more answers
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telo118 [61]

Answer:

Step-by-step explanation:

In algebra, the breakeven point is the point where two linear functions intersect. In marketing, this point represents the point where products neither make a profit nor incur a loss.

3 0
4 years ago
Which expression is equivalent to?...
stiks02 [169]

Answer:

B x^9 ∛ y

Step-by-step explanation:

(x^27 y) ^ (1/3)

x^27^(1/3) y^(1/3)

We can distribute the exponent a^b ^c = a^(b*c)

x^(27*1/3) y^(1/3)

x^9 y^(1/3)

3 0
4 years ago
Please help me with this one!
satela [25.4K]
Answer: C


Explanation: 100%
7 0
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