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Vikki [24]
3 years ago
14

For the last drop down answer is FG BC

Mathematics
1 answer:
Alisiya [41]3 years ago
5 0
I believe the answer would be DE is parallel to line segment FG
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Calculate the value of A please ?
Cloud [144]
A=7d+13
A=7(4)+13
A= 28+13
A=41
8 0
2 years ago
Look at the graph shown:
NNADVOKAT [17]
We are going to base the answer off of the y=mx+b form where m represents slope and b represents the y-intercept.

First, we know that b must be -1 because the line hits the y-axis when y is -1
So this leaves us with either the first or second choice

Then we choose two points to find the slope. I am using (0,-1) and (1,2). If you count the boxes, the y-value increases by 3 as the x-value increases by 1. So the slope is 3/1 or 3.

So then we know the answer is y=3x-1

Hope this helps 
4 0
3 years ago
Which statement best describes a method that can be used to sketch the graph. y = |x - 2| a. Translate the graph of y = |x| two
ser-zykov [4K]

f(x) + n - translate the graph of f(x) n units up

f(x) - n - translate the graph of f(x) n units down

f(x + n) - translate the graph of f(x) n units left

f(x - n) - translate the graph of f(x) n units right

--------------------------------------------------------------------------

We have

y = |x - 2|

f(x) = |x| → f(x - 2) = |x - 2|

<h3>Answer: c. Translate the graph of y = |x| two units right.</h3>
6 0
3 years ago
FaSSSSSSTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTT and thanks yall are fast
Mama L [17]

Answer:

120 degrees

Step-by-step explanation:

It's a vertical angle, meaning that it is congruent to the one on the opposite side of it.

5 0
3 years ago
Please help me I would really appreciate it.
Karo-lina-s [1.5K]

Given:

\overline{AB}\cong \overline {CD},\overline{BC}\cong \overline {DA}

To prove:

\Delta CDA\cong \Delta ABC

Proof:

In \Delta CDA\text{ and } \Delta ABC,

\overline{AB}\cong \overline {CD} because Given

\overline{BC}\cong \overline {DA} because Given

\overline{AC}\cong \overline {AC} because Reflexive property.

Corresponding sides of both triangles are congruent. So,

\Delta CDA\cong \Delta ABC because SSS

Therefore, the required missing values are: Given, \overline{BC}\cong \overline {DA}, Reflexive property ,\Delta CDA\cong \Delta ABC, SSS respectively.

5 0
3 years ago
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