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Mashcka [7]
3 years ago
7

Find a general solution of y" - 6y' +10y=0.

Mathematics
1 answer:
babymother [125]3 years ago
4 0

Answer:

y(x) = e^{3x} [Acos x+Bsin x]

Step-by-step explanation:

Given is a differential equation

y" - 6y' +10y=0.

We have characteristic equation as

m^2-6m+10 =0

The above quadratic cannot be factorised hence use formula

m=\frac{6+/-\sqrt{36-40} }{2} \\=3+i, 3-i

Hence general solution would be

y(x) = e^{3x} [Acos x+Bsin x]

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Step 1 of 5

(1). Familiarize.

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<em> </em>

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<em> </em>

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<em> </em>

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<em />

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Read 2 more answers
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