Question

A 0.98 M solution of calcium chloride with a volume of 0.25 L is diluted to form a 0.74 M solution. What is the new volume of the solution, to the nearest hundredth of a liter?

Answer 1

The new volume of the dilute solution is 0.33 L.

Explanation:

Using the law of Volumetric analysis, we can find the volume of the dilute solution from the stock solution or the concentrated solution of Calcium Chloride.

V1M1 = V2M2

V1 be the volume of the stock solution = 0.25 L

M1 being the molarity of the stock solution = 0.98 M

V2 be the volume of the dilute solution = ?

M2 being the molarity of the dilute solution = 0.74 M

We have to rearrange the above equation to find V2 as,

V2 = $\frac{V1M1}{M2}$

Now plugin the values as,

V2 = $\frac{0.25 L \times 0.98 M }{0.74 M}$

   = 0.33 L

So the new volume of the dilute solution is 0.33 L.