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2 years ago

Using the black numbers on the stopwatch to answer the questions.

Chemistry

2 answers:

maxonik [38]2 years ago

5 0

Answer: the top one is 5.3 s and the bottom one is tenths of seconds

Explanation:

qwelly [4]2 years ago

4 0

Answer: The answer to the top one is 5.3 s and the bottom one is tenths of seconds

Explanation: Hope this helps plz mark!! Thx

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What is the [OH-]if the pH of a solution 10.62

Lerok [7]

As we know,

pH + pOH = 14
Or,
pOH = 14 - pH

Putting Value of pH,

pOH = 14 - 10.62

pOH = 3.38

pOH is converted into [OH⁻] as follow,

[OH⁻] = 10⁻pOH ∴ -pOH is in power, 10 means antilog
press shift and click log button
[OH⁻] = 10⁻³°³⁸

[OH⁻] = 0.0004168

[OH⁻] = 4.16 × 10⁻⁴

5 0

3 years ago

Electromagnetic waves are used in many technological devices. Describe two examples of how energy from electromagnetic waves is

kykrilka [37]

Answer:

Electromagnetic waves are ubiquitous in nature (i.e., light) and used in modern technology—AM and FM radio, cordless and cellular phones, garage door openers, wireless networks, radar, microwave ovens, etc. These and many more such devices use electromagnetic waves to transmit data and signals.

Explanation:

i mean there's alot of stuff that have Electromagnetic waves in it i mean alot!

3 0

3 years ago

"In a test tube was add a piece of Zn and 2 mL of HCl (.1M). This reaction produced ZnCl2 and Hydrogen gas. This reactions is a:

omeli [17]

Answer:

d. A single replacement reaction.

Explanation:

The zinc replaces the hydrogen in the hydrochloric acid.

4 0

3 years ago

3 6. 9 TIME REMAINING 57:16 A substance is made up of slow-moving particles that have very little space between them. Based on t

Natalka [10]

Answer:

It is not a gas because its particles do not have large spaces between them.

Explanation:

Solids and liquids have a lot of particles with few spaces between them. Also, gas particles move rapidly in each direction.

5 0

3 years ago

A student placed 15.5 g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then

Ede4ka [16]

<u>Answer:</u> The mass of glucose in final solution is 1.085 grams

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$ ......(1)

Given mass of glucose = 15.5 g

Molar mass of glucose = 180.2 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$\text{Molarity of glucose solution}=\frac{15.5\times 1000}{180.2\times 100}\\\\\text{Molarity of glucose solution}=0.860M$

To calculate the molarity of the diluted solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated glucose solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted glucose solution

We are given:

$M_1=0.860M\\V_1=35.0mL\\M_2=?M\\V_2=0.500L=500mL$

Putting values in above equation, we get:

$0.860\times 35.0=M_2\times 500\\\\M_2=\frac{0.860\times 35.0}{500}=0.0602M$

Now, calculating the mass of glucose by using equation 1, we get:

Molarity of glucose solution = 0.0602 M

Molar mass of glucose = 180.2 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$0.0602=\frac{\text{Mass of glucose solution}\times 1000}{180.2\times 100}\\\\\text{Mass of glucose solution}=\frac{0.0602\times 180.2\times 100}{1000}=1.085g$

Hence, the mass of glucose in final solution is 1.085 grams

4 0

3 years ago