Question

Please need help on this one​

Answer 1

Answer:

m<X = 30°

Explanation:

Given:

Right-angled ∆VWX

$VW = \sqrt{43}$

$VX= 2\sqrt{43}$

Required:

m<X

SOLUTION:

Apply the trigonometric ratios formula.

To know which of the trigonometric ratios formula to apply, identify which of the side is opposite, adjacent or hypotenuse given the angle of reference, X.

Side VW is opposite to <X,

Side VX is the hypotenuse.

Therefore, trig ratio formula to use would be:

Sine of the angle of reference = opposite side/hypotenuse

Thus,

$sin(X) = \frac{VW}{VX}$

$sin(X) = \frac{\sqrt{43}}{2\sqrt{43}}$

$sin(X) = \frac{1}{2}$

$sin(X) = 0.5$

$X = sin^{-1}(0.5)$

$X = sin^{-1}(0.5)$

$X = 30$