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Alchen [17]
3 years ago
15

Hey can you please help me posted picture of question

Mathematics
2 answers:
kakasveta [241]3 years ago
8 0
We have the following equation:
 3x2 + 7x + 4 = 0
 Using the resolver we have:
 x = (- b +/- root (b2 - 4ac)) / 2a
 Substituting values we have:
 x = (- (7) +/- root ((7) 2 - 4 (3) (4))) / 2 (3)
 Rewriting:
 x = (- 7 +/- root (49 - 48)) / 6
 x = (- 7 +/- root (1)) / 6
 x = (- 7 +/- 1) / 6
 The results are:
 x = (- 7 + 1) / 6 = -6/6 = -1
 x = (- 7 - 1) / 6 = -8 / 6 = -4/3
 Answer:
 
x = -1
 
x = -4/3
 
option C and D
labwork [276]3 years ago
3 0
The solutions for the equation, 3x^2+7x+4=0 are -1 and -4/3.

So, the answer choices are C and D
You might be interested in
HELLPP. ITS URGENT.50 PTS
ICE Princess25 [194]

Answer:

  • 4x² - 13x + 8 = 0
  • 4x² - 11x + 5 = 0
  • 16x² - 41x + 1 = 0
  • x² + 5x + 4 = 0
  • x² - 66x + 64 = 0

Step-by-step explanation:

<u>Given</u>

  • α and β are roots of 4x²-5x-1=0

<u>Then the sum and product of the roots are:</u>

  • α+b = -(-5)/4 = 5/4
  • αβ = -1/4

(i) <u>Roots are α + 1 and β + 1, then we have:</u>

  • (x - (α + 1))(x - (β + 1)) = 0
  • (x - α - 1)(x - β - 1) = 0
  • x² - (α+β+2)x + α+β+ αβ + 1 = 0
  • x² - (5/4+2)x +5/4 - 1/4 + 1 = 0
  • x² - 13/4x + 2= 0
  • 4x² - 13x + 8 = 0

(ii) <u>Roots are 2 - α and 2 - β, then we have:</u>

  • (x + α - 2)(x + β - 2) = 0
  • x² + (a + β - 4)x - 2(α + β) + αβ + 4 = 0
  • x² + (5/4 - 4)x - 2(5/4) - 1/4 + 4 = 0
  • x² - 11/4x - 10/4 - 1/4 + 16/4 = 0
  • x² - 11/4x + 5/4x = 0
  • 4x² - 11x + 5 = 0

(iii) <u>Roots are α² and β², then:</u>

  • (x - α²)(x-β²) = 0
  • x² -(α²+β²)x + (αβ)² = 0
  • x² - ((α+β)² - 2αβ)x + (-1/4)² = 0
  • x² - ((5/4)² -2(-1/4))x + 1/16 = 0
  • x² - ( 25/16 + 1/2)x + 1/16 = 0
  • x² - 33/16x + 1/16 = 0
  • 16x² - 33x + 1 = 0

(iv) <u>Roots are 1/α and 1/β, then:</u>

  • (x - 1/α)(x - 1/β) = 0
  • x² - (1/α+1/β)x + 1/αβ = 0
  • x² - ((α+β)/αβ)x + 1/αβ = 0
  • x² - (5/4)/(-1/4)x - 1/(-1/4) = 0
  • x² + 5x + 4 = 0

(v) <u>Roots are 2/α² and 2/β², then:</u>

  • (x - 2/α²)(x - 2/β²) = 0
  • x² - (2/α² + 2/β²)x + 4/(αβ)² = 0
  • x² - 2((α+β)² - 2αβ)/(αβ)²)x + 4/(αβ)² = 0
  • x² - 2((5/4)² - 2(-1/4))/(-1/4)²x + 4/(-1/4)² = 0
  • x² - 2(25/16 + 8/16)/(1/16)x + 4(16) = 0
  • x² - 2(33)x + 64 = 0
  • x² - 66x + 64 = 0

3 0
3 years ago
Read 2 more answers
Solve the equation by completing the square 5x(x+6)=-50
motikmotik
First lets distribute the 5x 
5x^2 + 30x = -50

Lets divide every term by 5 
x^2 + 6x = -10 

To complete the square we have to half the b value, which in this case is 6. Then square it. 
Half of 6 is 3, 3 squared is 9 

Add that to both sides of the equation 
x^2 + 6x + 9 = -1 

Find the binomial squared
(x+3)^2 (If you're wondering how i got that please comment) 

(x+3)^2 = -1 

Take the square root of the equation of both sides
(x+3) = +/- i
x = -3 +/- i
x = -3 - i
and 
x = -3 + i


3 0
3 years ago
PLS HELO THANK YOUUUUU
baherus [9]

Answer:

divide 500 by 125.

You get 4x = 568

Answer is 142

Happy Learning

3 0
2 years ago
Help me please. I don’t understand this math. My math teacher is mean. :(((((
Verdich [7]

Answer:

The height of the given rectangular prism is 5cm.

Step-by-step explanation:

Given that the volume of the rectangular prism is 5cm^3

And length is \frac{3}{4} and width is 1\frac{1}{3}

That is V=5cm^3[/tex] , l=\frac{3}{4}cm and w=1\frac{1}{3}cm

We have the  volume of the rectangular prism V=lwh cubic centimeter

V=lwhcm^3

Substituting the values in above formula

5=\frac{3}{4}\times 1\frac{1}{3}\times h

5=\frac{3}{4}\times \frac{4}{3}\times h

5=1\times h

5=h

Rewritting as below

h=5cm

Therefore the height is 5cm

5 0
3 years ago
Read 2 more answers
What number is it? the difference of 9 and three times equals 69. find the number
Mazyrski [523]
Consider the number as 'n' (for now)
3n - 9 = 69
3n = 69 + 9
3n = 78
n = 78/3
n = 26
Therefore, The number is 26
8 0
3 years ago
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