Hey can you please help me posted picture of question

Mathematics

2 answers:

kakasveta [241]3 years ago

8 0

We have the following equation:
3x2 + 7x + 4 = 0
Using the resolver we have:
x = (- b +/- root (b2 - 4ac)) / 2a
Substituting values we have:
x = (- (7) +/- root ((7) 2 - 4 (3) (4))) / 2 (3)
Rewriting:
x = (- 7 +/- root (49 - 48)) / 6
x = (- 7 +/- root (1)) / 6
x = (- 7 +/- 1) / 6
The results are:
x = (- 7 + 1) / 6 = -6/6 = -1
x = (- 7 - 1) / 6 = -8 / 6 = -4/3
Answer:
x = -1
x = -4/3
option C and D

labwork [276]3 years ago

3 0

The solutions for the equation, $3x^2+7x+4=0$ are -1 and -4/3.

So, the answer choices are C and D

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HELLPP. ITS URGENT.50 PTS

ICE Princess25 [194]

Answer:

4x² - 13x + 8 = 0
4x² - 11x + 5 = 0
16x² - 41x + 1 = 0
x² + 5x + 4 = 0
x² - 66x + 64 = 0

Step-by-step explanation:

Given

α and β are roots of 4x²-5x-1=0

Then the sum and product of the roots are:

α+b = -(-5)/4 = 5/4
αβ = -1/4

(i) Roots are α + 1 and β + 1, then we have:

(x - (α + 1))(x - (β + 1)) = 0
(x - α - 1)(x - β - 1) = 0
x² - (α+β+2)x + α+β+ αβ + 1 = 0
x² - (5/4+2)x +5/4 - 1/4 + 1 = 0
x² - 13/4x + 2= 0
4x² - 13x + 8 = 0

(ii) Roots are 2 - α and 2 - β, then we have:

(x + α - 2)(x + β - 2) = 0
x² + (a + β - 4)x - 2(α + β) + αβ + 4 = 0
x² + (5/4 - 4)x - 2(5/4) - 1/4 + 4 = 0
x² - 11/4x - 10/4 - 1/4 + 16/4 = 0
x² - 11/4x + 5/4x = 0
4x² - 11x + 5 = 0

(iii) Roots are α² and β², then:

(x - α²)(x-β²) = 0
x² -(α²+β²)x + (αβ)² = 0
x² - ((α+β)² - 2αβ)x + (-1/4)² = 0
x² - ((5/4)² -2(-1/4))x + 1/16 = 0
x² - ( 25/16 + 1/2)x + 1/16 = 0
x² - 33/16x + 1/16 = 0
16x² - 33x + 1 = 0

(iv) Roots are 1/α and 1/β, then:

(x - 1/α)(x - 1/β) = 0
x² - (1/α+1/β)x + 1/αβ = 0
x² - ((α+β)/αβ)x + 1/αβ = 0
x² - (5/4)/(-1/4)x - 1/(-1/4) = 0
x² + 5x + 4 = 0

(v) Roots are 2/α² and 2/β², then:

(x - 2/α²)(x - 2/β²) = 0
x² - (2/α² + 2/β²)x + 4/(αβ)² = 0
x² - 2((α+β)² - 2αβ)/(αβ)²)x + 4/(αβ)² = 0
x² - 2((5/4)² - 2(-1/4))/(-1/4)²x + 4/(-1/4)² = 0
x² - 2(25/16 + 8/16)/(1/16)x + 4(16) = 0
x² - 2(33)x + 64 = 0
x² - 66x + 64 = 0

3 0

3 years ago

Read 2 more answers

Solve the equation by completing the square 5x(x+6)=-50

motikmotik

First lets distribute the 5x
5x^2 + 30x = -50

Lets divide every term by 5
x^2 + 6x = -10

To complete the square we have to half the b value, which in this case is 6. Then square it.
Half of 6 is 3, 3 squared is 9

Add that to both sides of the equation
x^2 + 6x + 9 = -1

Find the binomial squared
(x+3)^2 (If you're wondering how i got that please comment)

(x+3)^2 = -1

Take the square root of the equation of both sides
(x+3) = +/- i
x = -3 +/- i
x = -3 - i
and
x = -3 + i

3 0

3 years ago

PLS HELO THANK YOUUUUU

baherus [9]

Answer:

divide 500 by 125.

You get 4x = 568

Answer is 142

Happy Learning

3 0

2 years ago

Help me please. I don’t understand this math. My math teacher is mean. :(((((