About 750 different permutations
Answer: 13 sheets of paper
Step-by-step explanation:
We are given the dimensions of the box and the wrap paper:
Box:

Warp paper:

Now we need to find the surface area of the box and the area of the wrap paper:
Box:




Warp paper:

Dividing the area of the box by the area of the paper:

This means Angel's dad needs to purchase 13 sheets of wrapping paper.
Second one...................
Answer:
Step-by-step explanation:yes
1:3, Because you can simplify the numbers by dividing by two.