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NeX [460]
3 years ago
11

The median of the data set is 81 what number is missing in data set 82, 87, 77, 70, 80, 88

Mathematics
2 answers:
Gekata [30.6K]3 years ago
6 0
The number that missing is clearly 81
larisa [96]3 years ago
4 0
1. 70, 77, 80, 82, 87, 88
2. No numbers are missing!
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Angle Addition Crossword
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Answer:

Step-by-step explanation:

1). m∠AEC = m∠AEB + m∠BEC

                  = 21° + 37°

                  = 58°

2). m∠BED = m∠BEC + m∠CED

                   = 37° + 44°

                   = 81°

3). m∠IKF = m∠IKH + m∠HKG + m∠GKF

                = m∠IKH + m∠HKG + m∠IKH [Since, ∠IKH ≅ ∠GKF]

                = 2∠IKH + m∠HKG

         103° = 2∠IKH + 41°

   2(∠IKH) = 103 - 41

 m(∠IKH) = 31°

4). m∠AED = m∠AEB + m∠BEC + m∠CED

                  = 21° + 37° + 44°

                  = 102°

5). m∠JKG = 108°

    m∠JKG = m∠JKI + m∠IKH + m∠HKG

    108° = m∠JKI + 31° + 41°

    m∠JKI = 108° - 72°

    m∠JKI = 36°

6). m∠HKF = m∠GKF + m∠HKG

                  = m∠IKH + m∠HKG [Since, m∠GKF = m∠IKH]

                  = 31° + 41°

                  = 72°

7). m∠NQO = m∠MQN = 64°

8). m∠JKF = m∠JKI + m∠IKF

                 = 36° + 103°

                  = 139°

8). m∠MQO = 2(m∠NQO)

                    = 2(64)°

                    = 128°

9). m∠LQO = 156°

    m∠LQM = m∠LQO - m∠MQO

                    = 156° - 128°

                    = 28°

10. m∠NQP = m∠NQO + m∠OQP

                   = 64° + m∠LQM [Since ∠OQP ≅ ∠LQM]

                   = 64° + 28°

                   = 92°

5 0
3 years ago
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For f(x) =
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Answer:

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3 years ago
Hang 7 pictures with grandfather in the middle how many ways
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Two at the top (side by side)
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3 years ago
To calculate the cost of painting his silo, a farmer must find its height. The farmer uses a cardboard square to line up the top
tankabanditka [31]

Answer:

Height of the silo = 18 feet.

Step-by-step explanation:

From the figure attached BC is the length of the silo and the height of the farmer is 5 ft.

Farmer is standing at 8 ft distance from the silo.

From triangle AEC,

tan(∠CAE) = \frac{CE}{AE}

                 = \frac{5}{8}

m(∠CAE) = tan^{-1}(\frac{5}{8})

               = 32°

m∠BAE = 90° - 32° = 58°

From the triangle ABE,

tan58° = \frac{BE}{AE}

BE = 8tan58°

BE = 12.8 ft

Total height of the silo = BE + EC

                                         = 12.8 + 5

                                         = 17.8

                                         ≈ 18 ft          

Therefore, total height of the silo is 18 ft.

3 0
3 years ago
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