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3 years ago

What are the measures taken by counties to takle tropical storms

1 answer:

5 0

Control rooms in different departments and the district offices shall be immediately activated to function round the clock. The Departments shall ensure that their field officers are in position. Officers on leave shall be called back to duty forthwith.

• ODRAF and NDRF forces as well as teams of Fire services shall be deployed in advance to the areas likely to be affected by the cyclone and associated floods to carry out search & rescue operations and assist in evacuation operations.

• The Government will strive for ZERO CASUALTY. Collectors of the district likely to be affected must immediately prepare and keep the evacuation plan in respect of their districts ready, giving highest priority to most vulnerable villages/ habitations.

• Special care must be taken to shift the old, infirm, physically challenged, women and children to safer places and cyclone shelters much before the occurrence of the disaster.

• All cyclone and flood shelters shall be immediately checked and made ready to house the evacuees. The water supply, lighting and sanitation arrangements in the shelters shall be checked and curative measures taken, if any required.

• Immediate steps shall be taken to conduct mock drill in every cyclone and flood shelter. All equipment in the shelters shall be put to test run and the defective ones shall be repaired immediately.

• Other buildings as per requirement should also be identified by the district administration for use as shelter where water supply, lighting and sanitation arrangements are to be made.

• Proper arrangements must be in place to take care of the basic requirements of the evacuees especially food, medicine, light and water, etc. at the shelter places.

• As flood is always associated with cyclone, necessary boat arrangements must be made in advance to take up rescue and relief operations for likely flood.

• The water level of dams and MIPs must be carefully monitored and the storage level reduced if required. Further, rainfall in the upstreams of the rivers may be monitored regularly.

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How can early experiences modify the brain? Discuss impoverished and enriched environments in your answer.

natka813 [3]

Answer:

Our genetic predispositions and our specific environments interact. Environments can trigger gene activity, and genetically influenced traits can evoke responses from others.

As a child's brain develops, neural connections grow more numerous and complex. Experiences then prompt a pruning process, in which unused connections weaken and heavily used ones strengthen. Early childhood is an important period for shaping the brain, but throughout our lives our brain modifies itself in response to our learning.

Explanation:

^^^^^^^

4 0

2 years ago

Read 2 more answers

A rectangle has the following vertices. Find the area of the rectangle (-8,-6), (4, -6), (1,2), (8,2)

Tju [1.3M]

Answer: 84

Steps:

1. Find distance between (-8,-6) and (4,-6) using distance formula:

√ (4 - (-8))^2 + ((-6) - (-6))^2
√ (12)^2 + (0)^2
√ 144 + 0
√ 144
12

2. Find distance between (1,2) and (8,2) using distance formula:

√ (8-1)^2 + (2-2)^2
√ (7)^2 + (0)^2
√ 49 + 0
√ 49
7

3. Multiply found values to find area

A = l x w
A = 12 x 7
A = 84

3 0

3 years ago

Surface Area of a can is 517.8 cm^2. Maximize the volume of this can using the measured surface area.

mafiozo [28]

Answer:

$r = 5.24$ --- Radius

$h = 10.48$ --- Height

Explanation:

Given

Object: Can (Cylinder)

$Surface\ Area = 517.8cm^2$

Required

Maximize the volume

The surface area is:

$S.A = 2\pi r^2 + 2\pi rh$

Substitute 517.8 for S.A

$517.8 = 2\pi r^2 + 2\pi rh$

Divide through by 2

$258.9 = \pi r^2 + \pi rh$

Factorize:

$258.9 = \pi r(r + h)$

Divide through by $\pi r$

$\frac{258.9}{\pi r} = r + h$

Make h the subject

$h = \frac{258.9}{\pi r} - r$ --- (1)

Volume (V) is calculated as:

$V = \pi r^2h$

Substitute (1) for h

$V = \pi r^2(\frac{258.9}{\pi r} - r)$

Open Bracket

$V = 258.9r - \pi r^3$

Differentiate V

$V' = 258.9 - 3\pi r^2$

Set V' to 0

$0 = 258.9 - 3\pi r^2$

Collect Like Terms

$3\pi r^2 = 258.9$

Divide through by 3

$\pi r^2 = 86.3$

Divide through by $\pi$

$r^2 = \frac{86.3}{\pi}$

$r^2 = \frac{86.3*7}{22}$

$r^2 = \frac{604.1}{22}$

Take square root of both sides

$r = \sqrt{\frac{604.1}{22}$

$r = 5.24$

Recall that:

$h = \frac{258.9}{\pi r} - r$

Substitute 5.24 for r

$h = \frac{258.9}{\pi * 5.24} - 5.24$

$h = \frac{258.9*7}{22 * 5.24} - 5.24$

$h = \frac{1812.3}{115.28} - 5.24$

$h = 15.72 - 5.24$

$h = 10.48$

Hence, the dimension that maximize the volume is:

$r = 5.24$ --- Radius

$h = 10.48$ --- Height

7 0

3 years ago

Where my LGBTQ+ at? Don't be shy.

DaniilM [7]

Answer:

right here <333

Explanation:

4 0

2 years ago

The half-life of carbon-14 is about 5700 years. If you left those 100 carbon-14 atoms to sit around for 5700 years, how many wou

katovenus [111]

Answer:

50 atoms of carbon-14

Explanation:

From the question given above, the following data were obtained:

Original amount (N₀) = 100 atoms

Half-life (t½) = 5700 years

Time (t) = 5700 years

Amount that decay =?

Next, we shall determine the number of half-lives that has elapse. This can be obtained illustrated below:

Half-life (t½) = 5700 years

Time (t) = 5700 years

Number of half-lives (n) =?

n = t / t½

n = 5700 / 5700

n = 1

Next, we shall determine the amount remaining. This can be obtained as follow:

Original amount (N₀) = 100 atoms

Number of half-lives (n) = 1

Amount remaining (N) =?

N = 1/2ⁿ × N₀

N = 1/2¹ × 100

N = 1/2 × 100

N = 50 atoms

Finally, we shall determine the amount that decayed as follow:

Original amount (N₀) = 100 atoms

Amount remaining (N) = 50 atoms

Amount that decay =?

Amount that decay = N₀ – N

Amount that decay = 100 – 50

Amount that decay = 50 atoms

Therefore, 50 atoms of carbon-14 have decayed during the time.

8 0

2 years ago