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Artyom0805 [142]

3 years ago

7

1) The extent to which data points from a set of data differ from each other or from the true mean or average.

1 answer:

allsm [11]3 years ago

8 0

Answer:

measure of variability

Step-by-step explanation:

Measure of variability shows the extent in which data in a statically distribution differ from an average value as well as how they differ from each other. It shows how much the data falls from the center value (mean) showing the width of the distribution. The most used measures of variability are the range, interquartile range, variance, and standard deviation depending on the data to be measured.

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A Find the amount compounded annually on Rs 25,000 for 2 years if the rates of

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<em>Amount = Rs. 31360 when Rate = 12%</em>

Step-by-step explanation:

Given

$Principal, P = Rs.\ 25,000$

$Time, t = 2\ years$

$Rate; R_1 = 10\%$

$Rate; R_2 = 12\%$

Number of times (n) = Annually

$n = 1$

Required

Determine the Amount for both Rates

Amount (A) is calculated by:

$A = P(1 + \frac{r}{n})^{nt}$

When Rate = 10%, we have:

Substitute 25,000 for P; 2 for t; 1 for n and 10% for r

$A = 25000 * (1 + \frac{10\%}{1})^{1 * 2}$

$A = 25000 * (1 + \frac{10\%}{1})^{2}$

$A = 25000 * (1 + 10\%)^{2}$

Convert 10% to decimal

$A = 25000 * (1 + 0.10)^{2}$

$A = 25000 * (1.10)^{2}$

$A = 25000 * 1.21$

$A = 30250$

Hence;

<em>Amount = Rs. 30250 when Rate = 10%</em>

When Rate = 12%, we have:

Substitute 25,000 for P; 2 for t; 1 for n and 10% for r

$A = 25000 * (1 + \frac{12\%}{1})^{1 * 2}$

$A = 25000 * (1 + \frac{12\%}{1})^{2}$

$A = 25000 * (1 + 12\%)^{2}$

Convert 12% to decimal

$A = 25000 * (1 + 0.12)^{2}$

$A = 25000 * (1.12)^{2}$

$A = 25000 * 1.2544$

$A = 31360$

Hence;

<em>Amount = Rs. 31360 when Rate = 12%</em>

7 0

3 years ago