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3 years ago

A or B or C or D which expression??

Mathematics

1 answer:

zhenek [66]3 years ago

5 0

Answer:

option A

Step-by-step explanation:

Notice that you need to emulate the series: 1 + 5 + 25 + 125 + 625 (a five total term series)

with the indicated sums.

The first term in the your series (addition) has to be "1". This fact already gets rid of two of the suggested sums (B, and D) because their first term is $5^1=5$ .

So, now analyzing the options A and C, we notice that A has a sum from i=0 to 4 (which gives a total of five terms ao, a1, a2, a3, and a4, while option C has a total of six terms (from i = 0 to 5): a0, a1, a2, a3, a4, a5.

S, the obvious candidate is option A. So now evaluate the five terms corroborating that:

$5^0 + 5^1+5^2+5^3+5^4=\\=1+5+25+125+625$

Therefore, option A is the answer

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Consider the numberless roulette game at a casino. On a spin of the wheel, the ball lands in a space with color red (r), green (

Tatiana [17]

Answer:

a. Probability of Event A = 2.724037476607E−24

b. G19 = 0.123

c. P(Winning) = 0.475

Step-by-step explanation:

Given

Red (r) = 19

Green (g) = 19

Black (b) = 2

Total = 19 + 19 + 2 = 40

a. In 40 spins of the wheel, find the probability of event A = {19 reds, 19 greens, and 2 blacks}.

This is calculated as follows;

Let P(R) = Probability of Red

P(R) = 19/40

Let P(G) = Probability of Green

P(G) = 19/40

Let P(B) = Probability of Black

P(B) = 2/40

Total number of arrangement = 40!/(19!19!2!) = 27,569,305,764,000

Probability of Event A = 27,569,305,764,000 * (19/40)^19 * (19/40)^19 * (2/40)^19

Probability of Event A = 2.724037476607E−24

b. In 40 spins of the wheel, find the probability of the event G19 = {19 greens}.

Let P(G) = Probability of Green

P(G) = 19/40

Let P(Other) = Probability of any colour other than green = (2+19)/40

P(Other) = 21/40

Total = 40C19

G19 = 40C19 * (19/40)^19 * (21/40)^21

G19 = 0.125525075056335

G19 = 0.123 ---- Approximated

c. Given that you randomly choose to bet red and green only, what is the probability p that you bet a winner?

Let P(R) = Probability of Betting Red

P(R) = 19/40

Let P(G) = Probability of Betting Green

P(G) = 19/40

Let P(Winning) = Probability of Winning

P(Winning) = ½ * P(G) + ½ * P(R)

P(Winning) = ½ * 19/40 + ½ * 19/40

P(Winning) = ½(19/40 + 19/40)

P(Winning) = ½(38/40)

P(Winning) = 19/40

P(Winning) = 0.475

7 0

3 years ago

Read 2 more answers

Select the symbol that represents the phrase "at most."

anastassius [24]

Your answer will be c

4 0

3 years ago

I am trying Find the surface area of a prism or cube and it only has 3.5<br>

Kryger [21]

Surface Area of Cube = width^2 * 6 (sides of the cube)

Therefore, (3.5)^2 * 6 =

73.5 [whatever units]^2

4 0

2 years ago

For the class of 2013's prom Norman's dress shop sold cheaper dresses for $90 each and more expensive dresses for $140 each. The

Tema [17]

Answer:

Number of cheaper dresses sold is 35

Number of expensive dresses sold is 15

Step-by-step explanation:

Given:

Cost of cheaper dresses = $90

Cost of expensive dresses = $140

Total cost of the dresses = $5250

To Find:

Number of cheaper dress = ?

Number of expensive dress = ?

Solution:

Let

The number of cheaper dresses be x

The number of expensive dresses be y

(Number of cheaper dresses X cost of cheap dress) + (Number of Expensive dresses X cost of expensive dress) = $5250

$x \times90 +y \times 140 = 5250$ = $5250

It is given that the 20 more of the cheaper dresses than the expensive dresses is sold

So,

number of cheaper dress = 20 + number of expensive dress

x = 20 + y---------------------------------------(1)

$(20+y) \times90 +y \times 140 = 5250 = 5250$

$(20 \times 90 +y\times 90) +y \times 140= 5250$

$1800 + 90y+ 140y = 5250$

$1800 + 230y = 5250$

$230y =5250 -1800$

$230y = 3450$

$y = \frac{3450}{230}$

y = 15

Substituting y in (1)

x = 20 +15

x= 35

5 0

3 years ago

A mobile company charges a fixed rate of x cents per minute for the first 120 minutes of talk time and another rate of y cents p

patriot [66]

Answer:

$21.2

Step-by-step explanation:

From the problem given, we express them as algebra so that we can easily solve;

the total charge on a call greater than 120min is given as;

120x + y(n - 120) = total cost of call

where n is the number of minutes which is greater than 120;

Ethan paid $26.80 for 175 mins

n = 175min here;

120x + y(175 - 120) = 26.80

120x + 55y = 26.80 ----- (I)

$32.40 for 210 minutes

n = 210min

120x + y(210 - 120) = 32.4

120x + 90y = 32.4 ----- (II)

Now let us solve both equations for y and x;

120x + 55y = 26.80 ----- (I)

120x + 90y = 32.4 ----- (II)

subtract the two equations;

90y - 55y = 32.4 - 26.8

35y = 5.6

y = $\frac{5.6}{35}$ = 0.16cents

then x;

120x = 26.8 - 55y from equation I

120x = 26.8 - 55(0.16)

120x = 18

x = $\frac{18}{120}$ = 0.15cents

Find the cost of 140min of talk time;

n =140min;

= 120(0.15) + 0.16(140 - 120)

= 18 + 0.16(20)

= 18 + 3.2

= $21.2

4 0

3 years ago

A or B or C or D which expression??​

A or B or C or D which expression??