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Tpy6a [65]
3 years ago
15

Which system of linear inequalities Is represented by this graphed solution?

Mathematics
1 answer:
SashulF [63]3 years ago
7 0

Answer:

y ≥ 3x - 1

y < -\frac{1}{2}x+2

Step-by-step explanation:

Let the equation of the solid line passing through (x', y') given in graph is,

y = mx + b

Here m = slope of the line

b = y-intercept

Slope of the solid line =

                                 m = \frac{3}{1}

                                 m = 3

y - intercept 'b' = -1

Therefore, equation of the line will be,

y = 3x - 1

Since, shaded (blue) area is above the line, inequality that will represent the solution area will be,

y ≥ 3x - 1

For the dotted line,

Slope of the line (m) = \frac{\text{Rise}}{\text{Run}}

                                  = \frac{-2}{4}

                                  = -\frac{1}{2}

y-intercept (b) = 2

Equation of the dotted line → y = -\frac{1}{2}x+2

Since, shaded (grey color) area is below the dotted line,

Inequality representing the solution area will be,

y < -\frac{1}{2}x+2

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The equation of the line that is perpendicular to y = -5/2 x + 1 and passing through (10, 3) will be y = 2/5 x + 1.

<h3>What is the linear system?</h3>

A linear system is one in which the parameter in the equation has a degree of one. It might have one, two, or even more variables.

The equation of the perpendicular line will be given as

y = mx + c

The given equation is y = -5/2 x + 1.

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