Answer:
probability that both passes a defective item is 0.8742
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Step-by-step explanation:</h3>
probability that the first inspector misses is Pr( 1st misses)= 0.06
therefore the probability he does not miss is
Pr(1st passes)= 1 - Pr( 1st misses) = 1 - 0.06 = 0.94
probability that the second misses is Pr( 2nd misses) = 0.07
therefore probability that 2nd does not miss is
Pr( 2nd passes) = 1- Pr( 2nd misses) = 0.93
probability that both passes a defective item is Pr(1st passes)*Pr( 2nd passes)
= 0.93*0.94 = 0.8742
Answer:
Part A:
Part B:
and
Step-by-step explanation:
Part A:
The inicial concentration of the lemonade is 50%, and the volume is 4 quarts, and we will add x quarts of a lemonade with a concentration of 100%, so the total volume will be y, and the concentration will be 0.7, so we have that:
Using the value of y from the first equation in the second one, we have:
Part B:
If he shoots a total of ten targets, we can write the equation:
Each stationary target is 2 points, and each moving target is 3 points, so if the total points is 23, we have:
If we subtract the second equation by two times the first one, we have:
⇒
Answer: B
Step-by-step explanation:
68 divided by 204 gives you 0.33 so round to nearest tenth and and go to 0.31 and then convert to percent and you have 31%
Maybe after the dog walked the street
Hi there,
Recall how 7 packs for gum sell for $29.33.
Before we can calculate how much it would cost to sell 3 packs of gum, we must calculate how much it would first cost to sell 1 pack of gum.
The cost of 1 pack of gum is the current total cost divided by the total amount of gum packs you receive at that price.
In this case, the total cost is $29.33, and we receive 7 gum packs at that price.
Therefore, the cost of 1 pack of gum is , which equates to $4.19.
We now know that each pack of gum costs $4.19.
Hence, 3 packs of gum would cost three times that price.
The cost of 3 packs of gum is $12.57.
Hope that helps!