None, Karen doesn't read.
Answer:
a) 18
b) 2.101
Step-by-step explanation:
a) What are the degrees of freedom for Student's t distribution when the sample size is 19?
Degrees of freedom = n - 1
Where n = sample size
= 19 - 1
= 18
b) Use the Student's t distribution to find tc for a 0.95 confidence level when the sample is 19.
(Round your answer to three decimal places.)
We would be determining these using the t distribution table
1 - 0.95 = 0.05 ( for two tailed)
Or
0.05/2 = 0.025(one - tailed)
Hence, the tc(test score) for a 0.95 confidence level when the sample is 19 is 2.101
Hi,
Get knowledge *throw math book at brain*
8 x 8 x 8 is 512 so its not a or b, add that to 6 times 6 and it equals d 546,
Answered by Britton have a nice day:)
Answer:
$66
Step-by-step explanation:
T=200-18W
where W is number of weeks
T=200-18(8)
T=200-144
T=66
Answer
Step-by-step explanation:
