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melamori03 [73]
3 years ago
12

Last year, Rusty’s Tools experienced $67,550 in net sales, creating a gross profit of $50,338. If Rusty had a total operating ex

pense of $35,200 last year, what was his net profit margin?
Mathematics
2 answers:
goldfiish [28.3K]3 years ago
6 0

Answer:

22.4%

Please make this answer the brainliest when you get the chance. Thank you.


zzz [600]3 years ago
5 0

Answer:

Net profit margin is 22.41%

Step-by-step explanation:

Rusty's Tool experienced $67550 in net sales, creating a gross profit of $50338.

If Rusty had a total operating expense of $35200 then we have to find the net profit margin.

Since profit $50338 includes the operating expense of $35300 then net profit will be = $50338 - $33500 = $15138

Now the selling price is given as $67550.

So profit margin will be = \frac{\text{Net profit}}{\text{Selling price}}\times (100)

Profit margin = \frac{15138}{67550}\times 100=22.41%

Therefore, answer is profit margin = 22.41%

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Please help thank you and show all work.
Daniel [21]
Question 1:

Look at the first attached image.

We want to solve for the height of the smaller building. Let's start by making a right triangle with angle of 15 degrees and adjacent side of 51 m.

Let's solve for the other leg. Multiply the tangent with 51 m to get the length of the other leg.

51*tan(15)
\approx 14

Now, subtract that from 207 to get the height of the smaller building.

207-14=193

That's your answer.

Question 2:

The angle of elevation is congruent to the angle of depression because they are alternate interior angles.

Thus, you can choose the 1st and 4th choices as your answer.

Question 3:

Look at the second attached image.

Angle E is congruent to angle D for the same reasons mentioned in the last question.
We can create an equation.

3x+1=2(x+8)

Distributive property

3x+1=2x+16

Subtract both sides by 1 and 2x

x=15

Since E and D are congruent, just plug this value into one of the equations for E or D. You get 46.

The third choice is your answer. Hope this helps! :)

6 0
3 years ago
R/3 + 5 &lt; 8<br><br> please help
Feliz [49]

Answer:

r<9

Step-by-step explanation:

r/3 + 5 < 8

Subtract 5 from each side

r/3 + 5-5 < 8-5

r/3 < 3

Multiply each side by 3

r/3 *3 <3*3

r<9

3 0
3 years ago
Find the median mode range and any outliers. Then describe the data using them 77777,88,555,6,99,10101010,12
umka2103 [35]

Answer:

The median = 5

The mode  = 7

Range = 5

Outliers= None

Step-by-step explanation:

The median is the  value of the middle term.

The median is that value which divides the data into two equal halves.

7,7,7,7,7,8,8,5,5,5,6,9,9,10,10,10,10,12

There are 18 terms . So the middle term would be 9th term value= 5

The mode is the value which is repeated the most. = 7

Range is the difference between the highest and lowest value.= 12- 7= 5

The interquartile range, IQR= q3 - q1 where q3= 10 and q1= 7

IQR= 10 −7=3

The inner fences can be found out by

q1−(1.5*IQR) and q3+(1.5*IQR)

=7−(1.5*3) and 10+(1.5*3)

Inner fences: 2.5 and 14.5

The outer fences are q1−(3*IQR) and q3+(3*IQR)

=7−(3*3) and 10+(3*3)

Outer fences: -2 and 19

So if there are any outliers in this data set, they will either be less than -2 or greater than 19. But there are no outliers.

6 0
3 years ago
The recycling center collected 48,000 ounces of
Leona [35]

Answer: 1.5 tons

Step-by-step explanation:

Given

The recycling center collected 48,000 ounces of aluminum can

An ounce is the unit of weight and it can be expressed in tons as

1\ \text{ounce}=3.125\times 10^{-5}\ \text{tons}

\therefore 48,000\ \text{ounces} \equiv\ 3.125\times 10^{-5}\times 48,000=1.5\ \text{tons}

8 0
3 years ago
Jake is using a horse trailer to take his horses to his new ranch. 1 Horse= 1,200 lb Trailer= 2,700 lb Jake's truck can tow a ma
Kitty [74]

Answer:

Jack can take only 1 horse on his trailer to be towed by the truck without going over the maximum weight the truck.

Step-by-step explanation:

Given:

Weight of 1 horse = 1,200 lb

Weight of trailer = 2,700 lb

Jacks'truck can tow a maximum of 5000 pounds.

To find the maximum number of horses Jack can take in his trailer without going over the maximum weight his truck can tow.

Solution:

Let the maximum number of horses that Jack can take be = x

Using unitary method to find weight of x horses.

If 1 horse weights = 1,200 lb

Then x horses will weight in lbs = 1,200\times x = 1,200x

Total weight of horses and trailer in lbs = 1200x+2700

Since the maximum weight the truck can tow = 5,000 lb, so the inequality can be given as:

1200x+2700\leq5000

Subtracting both sides by 2700.

1200x+2700-2700\leq5000-2700

1200x\leq2300

Dividing both sides by 1200.

\frac{1200x}{1200}\leq\frac{2300}{1200}

x\leq1.91

From the inequality solution for x, we can conclude that Jack can take only 1 horse on his trailer to be towed by the truck without going over the maximum weight the truck.

3 0
3 years ago
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