Well Chimpanzees have a different living of humans. They also have a different habitat. They eat different food than a human would.
Ans.
Lac (lactose) operon in a type of bacterial operon, which shows a cluster of genes that are regulated by a single promoter. It is composed of an operator, promoter, a terminator, and three structural genes (lacA, lacY, and lacZ), which are responsible for the transport and breakdown of lactose.
The lac operon is an inducible operon as it gets activated in the presence of lactose and expressed its functional genes in the form of proteins (or enzymes) for lactose metabolism.
Thus, the correct answer to be fill in first blank is 'inducible' and in second blank is 'lactose.'
A gene is a small section of DNA?<span> that contains the instructions for a </span>specific<span>molecule, usually a </span>protein?. The purpose of genes?<span> is to store information. Each gene contains the information required to build </span>specific proteins<span> needed in an</span>organism<span>.</span>
Answer:
The genotype of the randomly chosen F1 parent plant is "Tt"
Explanation:
Let "T" represents the allele for tall height characteristic of plant and "t" represents the allele for short height characteristic of plant.
Given -
Two phenotypically tall heterozygous pea plants are crossed to one another.
Genotype of tall heterozygous pea plants would be "Tt"
F1 Generation -
Tt * Tt
TT, Tt, Tt, tt
Now, it is given that a phenotypically tall F1 progeny plant is randomly chosen and mated to a phenotypically dwarf pea plant.
Genotype of phenotypically dwarf pea plant would be "tt"
Also, it is given that some of the F2 offspring from this mating are phenotypically dwarf this implies that progeny selected from F1 generation must have an allele for short height characteristics i.e "t"
Therefore,
in F2 generation cross will take between tt * Tt
thereby producing Tt, Tt, tt, tt
Therefore, the genotype of the randomly chosen F1 parent plant is "Tt"
