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3 years ago

Can some one help me.

Mathematics

2 answers:

Novay_Z [31]3 years ago

7 0

You have to collect the like terms and then solve the equation

alina1380 [7]3 years ago

3 0

Answer:

x = ± 2, x = 3

Step-by-step explanation:

note that x = 2 gives

2³ - 3(2)² - 4(2) + 12 = 8 - 12 - 8 + 12 = 0

Hence x = 2 is a root and (x - 2) is a factor

x³ - 3x² - 4x + 12 ÷ (x - 2)

= (x - 2)(x² - x - 6)

= (x - 2)(x + 2)(x - 3), hence

(x - 2)(x + 2)(x - 3) = 0

equate each factor to zero and solve for x

x - 2 = 0 ⇒ x = 2

x + 2 = 0 ⇒ x = - 2

x - 3 = 0 ⇒ x = 3

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3 years ago

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mrs_skeptik [129]

Given:

Line a passes through (2, 10) and (4, 13).

Line b passes through (4, 9) and (6, 12).

Line c passes through (2, 10) and (4, 9).

To find:

Which of the lines, if any are perpendicular.

Solution:

If a line passes through two points, then the slope of line is

$m=\dfrac{y_2-y_1}{x_2-x_1}$

Line a passes through (2, 10) and (4, 13). So, slope of this line is

$m_a=\dfrac{13-10}{4-2}=\dfrac{3}{2}$

Line b passes through (4, 9) and (6, 12). So, slope of this line is

$m_b=\dfrac{12-9}{6-4}=\dfrac{3}{2}$

Line c passes through (2, 10) and (4,9). So, slope of this line is

$m_c=\dfrac{9-10}{4-2}=\dfrac{-1}{2}$

Product of slopes of to perpendicular lines is -1.

$m_a\cdot m_b=\dfrac{3}{2}\times \dfrac{3}{2}=\dfrac{9}{4}\neq -1$

$m_b\cdot m_c=\dfrac{3}{2}\times \dfrac{-1}{2}=\dfrac{-3}{4}\neq -1$

$m_a\cdot m_c=\dfrac{3}{2}\times \dfrac{-1}{2}=\dfrac{-3}{4}\neq -1$

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3 years ago

What is the answer for 136.9 divided by .77 showing work

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3 years ago

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The measure of <1 = 20x + 21 and the measure of <2 = 30x - 29.

geniusboy [140]

Answer:

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Step-by-step explanation:

Vertical angles are equal, and and 2 are indeed vertical angles. They are the "top" and "bottom" of the x formed. So you can use this.

angle 1 = angle 2

20x + 21 = 30x - 29

50 = 10x

5 = x

So just plug this in.

20x + 21

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30x - 29

30(5) - 29

121

So both are 121.

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3 years ago

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rusak2 [61]

Answer:

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7 0

2 years ago