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3 years ago

Help Please!! I'm confused about this... (you can explain or screenshot the graph and show where the points are)

Mathematics

1 answer:

saul85 [17]3 years ago

8 0

Your first step is to isolate y and put it into slope-intercept form.

Then graph

See screenshots below

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1. $200 is deposited into an account that earns 6% simple interest

katen-ka-za [31]

Answer:

$260

Step-by-step explanation:

0.06 x 200 = 12

12 x 5 = 60

200 + 60 = 260

3 0

3 years ago

The sum of three numbers is 10. Two times the second number minus the first number is equal to 12.

eimsori [14]

Answer:

-10,1,19

Step-by-step explanation:

x+y+z = 10 (Equation 1)

2y-x= 12 (Equation 2)

x-y+2z = 7 (Equation 3)

(Equation 2): -x = -2y+12

x = 2y-12 (Equation 4)

(Equation 1) - (Equation 3): 2y-z = 3

-z = -2y+3

z = 2y-3 (Equation 5)

Substitute (4) and (5) into (1)

x+y+z = 10

(2y-12)+y+(2y-3) = 10

5y-15 = 10

5y = 5

y=1

Substitute y=1 into (2)

2y-x= 12

2(1)-x= 12

2-x= 12

-x= 12-2

-x= 10

x= -10

Substitute y=1 and x=-10 into (1)

x+y+z = 10

-10+1+z = 10

z-9 = 10

z = 10+9

z = 19

Order: x = -10, y = 1, and z = 19

8 0

3 years ago

Read 2 more answers

2<img src="https://tex.z-dn.net/?f=%20%203%5E%28x%2B7%29%20%3D%20%209%5E%28x-1%29" id="TexFormula1" title=" 3^(x+7) = 9^(x-1)"

DaniilM [7]

3(x + 7) = 9(x - 1)
3(x) + 3(7) = 9(x) - 9(1)
3x + 21 = 9x - 9
- 3x - 3x 
 21 = 3x - 9
 + 9 + 9
 30 = 3x
 3 3
 10 = x

4 0

3 years ago

I WILL GIVE BRAINLIEST..... The perimeter of a triangle is 22cm. if one of the sides is 9cm, find the other sides if the area of

love history [14]

Other sides are 6 and 7.

3 0

3 years ago

Match the key aspect of a function's graph with its meaning.

Margarita [4]

Answer:

Part 1) Intervals of the domain where the graph is above the x-axis (f(x) > 0)

Part 2) location on graph where input is zero (y-intercept)

Part 3) location on graph where output is zero (x-intercept)

Part 4) Intervals of the domain where the graph is below the x-axis (f(x) < 0)

Step-by-step explanation:

Verify each case

Part 1) we have

Intervals of the domain where the graph is above the x-axis

we know that

If the graph is above the x-axis, then the value of f(x) is positive

therefore

f(x) > 0

Part 2) we have

location on graph where input is zero

Let

x ---> the independent variable or input value

f(x) ---> the dependent variable or output value

we know that

The y-intercept is the value of f(x) (output value) when the value of x (input value) is zero

therefore

y-intercept

Part 3) we have

location on graph where output is zero

Let

x ---> the independent variable or input value

f(x) ---> the dependent variable or output value

we know that

The x-intercept is the value of x (input value) when the value of the function f(x) (output value) is zero

therefore

x-intercept

Part 4) we have

Intervals of the domain where the graph is below the x-axis

we know that

If the graph is below the x-axis, then the value of f(x) is negative

therefore

f(x) < 0

5 0

3 years ago