If a 3 foot pole casts a 4 foot shadow, how high a pole casts a 72 foot shadow?

Someone help me please. :(

blsea [12.9K]

6x 24 /5 = 68 feet is the sender

7 0

3 years ago

Write an equation for the following word problem.

Whitepunk [10]

<em><u>Answer:</u></em>

Option 1 or 16 + h = 24

<em><u>Step-by-step explanation:</u></em>

Tyrone ate 16 hamburgers today.

Tyrone had 24 hamburgers.

Hamburger = h.

We want to find how much Tyrone had left so:

h = 24 - 16

OR (we can move 16 to the other side)

h + 16 = 24

Option 1 is the answer

6 0

3 years ago

Which are vertical angles?

miv72 [106K]

Vertical angles are angles opposite each other where two lines cross

5 0

3 years ago

A decimal is considered as

dalvyx [7]

<h3>Answer: B) real number</h3>

Explanation:

Something like 3.5 = 7/2 is a rational number because its a fraction of two integers.

While on the other hand, the constant pi = 3.14159... is irrational because we cannot write pi as a fraction of two integers. We can get approximations like 22/7, but not a perfect exact match.

Both types of numbers, rational and irrational, are under the umbrella of the real number system. Any real number is a string of decimal digits. Sometimes it might be a whole number, but fractional values can be included as well. The decimal number may terminate, or it may repeat, or it may go on forever without a pattern.

In short, any number you can think of is a real number assuming your teacher hasn't covered complex numbers (or imaginary numbers) just yet.

5 0

2 years ago

Read 2 more answers

The amount of calories consumed by customers at the Chinese buffet is normally distributed with mean 2885 and standard deviation

aliina [53]

Answer:

a. X~N(2,885, 651)

b. 0.086291

c. 0.00058

d. 3213.10 calories

Step-by-step explanation:

a. -A normal distribution is expressed in the form X~N(mean, standard deviation).

-Let X a random variable denoting the number of calories consumed.

-X is a is a normally distributed random variable with mean 2885 and standard deviation 651.

-This distribution is expressed as X~N(2,885, 651)

b. The probability that less than 2000 calories are consumed is calculated using the formula:

$P(X$

#substitute the given values in the formula to solve for P:

$P(X$

Hence, the probability of consuming less than 2000 calories is 0.08691

c. The proportion of customers consuming more than 5000 calories is calculated as:

$P(X>x)=P(z>\frac{\bar X-\mu}{\sigma})\\\\=P(Z>\frac{5000-2885}{651})\\\\=P(z>3.2488)\\\\=1-0.99942\\\\=0.00058$

Hence, the proportion of customers consuming over 5000 calories is 0.00058

d. The least amount of calories to get the award is calculated as:

1% is equivalent to a z value of 0.50399.

-We equate this to the formula to solve for the mean consumption:

$0.01=P(z>\frac{\bar X-\mu}{\sigma})\\\\=P(z>\frac{\bar X-2885}{651})\\\\\1\%=0.50399 \\\\\frac{\bar X-2885}{651}=0.50399 \\\\\bar X=0.50399\times 651+2885\\\\=3213.09$

Hence, the least amount of calories consumed to qualify for the award is 3213.10 calories.

8 0

4 years ago