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Trava [24]
4 years ago
15

In △ABC, AB = BC = 20, DE = 5. Find BD.

Mathematics
2 answers:
givi [52]4 years ago
6 0

Answer: BD = 7.5

Step-by-step explanation:

EC = DB = 20-5/2 = 7.5

gtnhenbr [62]4 years ago
5 0
About 27 AB is the answer
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Help me with question 1 please
GrogVix [38]

Answer:

DB = 6

Step-by-step explanation:

See the attached figure to the question.

Since O is the center of the given circle, so AB and CD are diameters of the circle.

Hence, AO = CO = OD = OB = radius of the circle = 6

In Δ OAC, we have AO = OC. Hence, ∠ A = ∠C = 60° {Given that ∠OAC = 60°}

So, ∠ AOC will automatically become 60°. {As the sum of all the angles of a triangle is 180°}

So, Δ AOC is equilateral triangle.

Now, ∠ AOC = ∠ BOD = 60°  {Since, they are vertically opposite angles}

Now, in Δ BOD, we have DO = OB. Hence, ∠ D = ∠ B = 60° {As the sum of all the angles of a triangle is 180°}

So, Δ BOD is also an equilateral triangle.

So, DB = BO = DO = 6. (Answer)

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3 years ago
2556 25<br> 5625/25<br><br> How do you divide 5625 by 25?
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Step-by-step explanation:

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3 0
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In ΔGHI, i = 75 cm, h = 12 cm and ∠H=22°. Find all possible values of ∠I, to the nearest 10th of a degree.
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Answer:

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Step-by-step explanation:

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sveticcg [70]
The answer my dear friend is 260
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For this case we evaluate the function when x = 0
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