Answer:
x=1
y=s
z=1
Step-by-step explanation:
(x, y, z)=(1, 0, 1)
Substitute 0 for y

Confirming if t=0 satisfy the other equation
x = e^−2t cos 4t = e^−2(0)cos(4*0)
= e^(0)cos(0) = 1
z = e^−2t = e^−2(0) = 0
Therefore t=0 satisfies the other equation
Finding the tangent vector at t=0

The vector equation of the tangent line is
(1, 0, 1) +s(0,1,0)= (1, s, 1)
The parametric equations are:
x=1
y=s
z=1
Answer:
16,384 or 2^14
Step-by-step explanation:
4^12= 4*4*4*4*4*4*4*4*4*4*4*4=16,777,216
4^5= 4*4*4*4*4=1024
16,777,216/1024=16,384
16,384=2^14
I’m not really sure if it correct, g(1)=0 or g(1)=1??
Answer:
(1,2)
Step-by-step explanation:
half it! :)