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user100 [1]
2 years ago
5

Determine the domain of the following graph:

Mathematics
1 answer:
dedylja [7]2 years ago
8 0

Answer:

Domain: -5, -3, -2, 1, 3

Step-by-step explanation:

Find all the points on the x-axis that line up with the line shown on the graph.

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The digits 2 comma 3 comma 4 comma 5 comma and 2, 3, 4, 5, and 6 are randomly arranged to form a​ three-digit number. ​ (Digits
iren2701 [21]
There are total of 5 digits, of which we arrange 3 of them.
Therefore using permutations we can find total possible 3-number combinations.
5P3 = 5*4*3 = 60

To be greater than 600 means first digit must be 6. (1 possibility)
A number is even only if last digit is even, 2 or 4.  (2 possibilities)
The 2nd digit then can only be 3,5, (2 or 4).    (3 possibilities)
The total possible even 3-digit numbers greater than 600 is product of each digit's possibilities.
---> 1*3*2 = 6

Therefore probability is 6/60 = 1/10.
5 0
3 years ago
What is the fraction for What is the fraction for 0.21
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The fraction for 0.21 would be 21/100
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In Jim's class, 5 times as many students take the bus as those who walk, a total of 24 students walk or take the bushow many mor
Veseljchak [2.6K]
4.8 students take bus

not sure if right though

but hope it helps c:



7 0
3 years ago
Read 2 more answers
During a thunderstorm​ yesterday, 600 millimeters of rain fell in 30 minutes. What is the unit rate for millimeters per​ minute?
blagie [28]

Answer:

I think it would be 50 millimeters per second

Step-by-step explanation:

600/30

7 0
3 years ago
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The amount of time a passenger waits at an airport check-in counter is random variable with mean 10 minutes and standard deviati
Stolb23 [73]

Answer:

(a) less than 10 minutes

= 0.5

(b) between 5 and 10 minutes

= 0.5

Step-by-step explanation:

We solve the above question using z score formula. We given a random number of samples, z score formula :

z-score is z = (x-μ)/ Standard error where

x is the raw score

μ is the population mean

Standard error : σ/√n

σ is the population standard deviation

n = number of samples

(a) less than 10 minutes

x = 10 μ = 10, σ = 2 n = 50

z = 10 - 10/2/√50

z = 0 / 0.2828427125

z = 0

Using the z table to find the probability

P(z ≤ 0) = P(z < 0) = P(x = 10)

= 0.5

Therefore, the probability that the average waiting time waiting in line for this sample is less than 10 minutes = 0.5

(b) between 5 and 10 minutes

i) For 5 minutes

x = 5 μ = 10, σ = 2 n = 50

z = 5 - 10/2/√50

z = -5 / 0.2828427125

= -17.67767

P-value from Z-Table:

P(x<5) = 0

Using the z table to find the probability

P(z ≤ 0) = P(z = -17.67767) = P(x = 5)

= 0

ii) For 10 minutes

x = 10 μ = 10, σ = 2 n = 50

z = 10 - 10/2/√50

z = 0 / 0.2828427125

z = 0

Using the z table to find the probability

P(z ≤ 0) = P(z < 0) = P(x = 10)

= 0.5

Hence, the probability that the average waiting time waiting in line for this sample is between 5 and 10 minutes is

P(x = 10) - P(x = 5)

= 0.5 - 0

= 0.5

3 0
3 years ago
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