All categories

2 years ago

What do we call a polynomial with 5 terms

Mathematics

1 answer:

Dafna11 [192]2 years ago

6 0

Answer:

You call an expression with a single term a monimial, an expression with two terms is a binomial and an expression with three terms is a trinomial. An expression with more than three terms is named simply by it's number of terms. For example a polynomial with five terms is called a five-term polynomial.

Step-by-step explanation:

You might be interested in

SUSTITUTION 3X-6Y=2 5X+4Y=1

Montano1993 [528]

3x - 6y = 2
5x + 4y = 1

(-1/3, -1/6)

~Hope I helped!~

6 0

3 years ago

What is the answer to -x/2+5=-1

podryga [215]

The answer to the problem is x=7. Here is the work:

5 0

2 years ago

A given field mouse population satisfies the differential equation dp dt = 0.5p − 410 where p is the number of mice and t is the

ohaa [14]

Answer:

a) $t = 2 *ln(\frac{82}{5}) =5.595$

b) $t = 2 *ln(-\frac{820}{p_0 -820})$

c) $p_0 = 820-\frac{820}{e^6}$

Step-by-step explanation:

For this case we have the following differential equation:

$\frac{dp}{dt}=\frac{1}{2} (p-820)$

And if we rewrite the expression we got:

$\frac{dp}{p-820}= \frac{1}{2} dt$

If we integrate both sides we have:

$ln|P-820|= \frac{1}{2}t +c$

Using exponential on both sides we got:

$P= 820 + P_o e^{1/2t}$

Part a

For this case we know that p(0) = 770 so we have this:

$770 = 820 + P_o e^0$

$P_o = -50$

So then our model would be given by:

$P(t) = -50e^{1/2t} +820$

And if we want to find at which time the population would be extinct we have:

$0=-50 e^{1/2 t} +820$

$\frac{820}{50} = e^{1/2 t}$

Using natural log on both sides we got:

$ln(\frac{82}{5}) = \frac{1}{2}t$

And solving for t we got:

$t = 2 *ln(\frac{82}{5}) =5.595$

Part b

For this case we know that p(0) = p0 so we have this:

$p_0 = 820 + P_o e^0$

$P_o = p_0 -820$

So then our model would be given by:

$P(t) = (p_o -820)e^{1/2t} +820$

And if we want to find at which time the population would be extinct we have:

$0=(p_o -820)e^{1/2 t} +820$

$-\frac{820}{p_0 -820} = e^{1/2 t}$

Using natural log on both sides we got:

$ln(-\frac{820}{p_0 -820}) = \frac{1}{2}t$

And solving for t we got:

$t = 2 *ln(-\frac{820}{p_0 -820})$

Part c

For this case we want to find the initial population if we know that the population become extinct in 1 year = 12 months. Using the equation founded on part b we got:

$12 = 2 *ln(\frac{820}{820-p_0})$

$6 = ln (\frac{820}{820-p_0})$

Using exponentials we got:

$e^6 = \frac{820}{820-p_0}$

$(820-p_0) e^6 = 820$

$820-p_0 = \frac{820}{e^6}$

$p_0 = 820-\frac{820}{e^6}$

8 0

3 years ago

Help Will Give Brainlist

Olin [163]

Answer:

3.14 million

Step-by-step explanation:

10.676 - 7.536 = 3.14

To check

7.536 + 3.14 = 10.676

4 0

2 years ago

Please help me find the value of x

Novay_Z [31]

Set the equations to equal each other because the angles are equal.
8x - 63 = 4x - 27
+63 on both sides
8x = 4x + 36
-4x on both sides
4x = 36
/4 on both sides
x = 9

Answer:
x = 9

7 0

2 years ago

Read 2 more answers