We re-write the system of equations by using the fact that we need the y-values to be the same, so we equal them:
- 10 x + 7/3 = - 10 x + 1/10
We notice then, as we try to solve for the one unknown left (x), that as we add 10 x on both sides of our new equation, all the terms in "x" go away, as shown below:
- 10 x + 10 x + 7/3 = - 10 x + 10 x + 1/10
combine like terms:
7/3 = 1/10
so we notice we have ended up with a ridiculous solution, a statement that tells us that 7/3 equals 1/10 which is mathematically a FALSE statement. Therefore, we conclude that the system has NO solutions, given that there are no possible x or y values that can ever produce a logical answer.
We select therefore the option No solution, among the list of answers.
Answer: 18 quarts.
Step-by-step explanation: x = ((9) / (3/4)) * (1 1/2)
x = ((9) * (4/3)) * (1 1/2)
x = (36/3) * (1 1/2)
x = (12) * (1 1/2)
x = (12) * (3/2)
x = 18
Answer:
576 cuboids
Step-by-step explanation:
Let
x -----> the length side of the cube
n -----> number of cuboids that are needed
we know that
The volume of the cuboid is equal to

The volume of the cube is equal to

Find the number of cuboids that are needed

n*24 must be a perfect cube
so
The minimum value that satisfied n to make n*24 a perfect cube is n=576

Answer:
False
Step-by-step explanation:
It would come after both it is smaller than both numbers
<h3>Given</h3>
A regular polygon with area 500 ft² and apothem 10 ft
Cost of fence is $7.95 per ft
<h3>Find</h3>
Part III The cost of fence around an area scaled to 60 times the size
<h3>Solution</h3>
You don't want to think too much about this, because if you do, you find the regular polygon has 3.087 sides. The closest approximation, an equilateral triangle, will have an area of 519.6 ft² for an apothem of 10 ft.
For similar shapes of scale factor "s", the larger shape will have an area of s² times that of the smaller one. Here, it appears the area scale factor s² is 60, so the linear scale factor is
... s² = 60
... s = √60 ≈ 7.7460
The perimeter fence of the 500 ft² area is presumed to be 100 ft long (twice the area of the polygon divided by the apothem—found in Part I), so the perimeter fence of the industrial farm is ...
... (100 ft)×7.7460 = 774.60 ft
and the cost to construct it is
... ($7.95/ft)×(774.60 ft) ≈ $6158