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mojhsa [17]
3 years ago
11

Which logarithmic equation is equivalent to the exponential equation below? e^a=55

Mathematics
1 answer:
Volgvan3 years ago
7 0

Answer:

The answer is B.

e^a=55

Taking log on both sides,

lne^a = ln 55

a lne= ln55

a= ln55.

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He would need to pay $60 each week

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180 divided by 3
3 0
3 years ago
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Please help! Giving brainliest if you include explanation bc I need to learn this
zhannawk [14.2K]

Answer:

B is the most reasonable answer

Step-by-step explanation:

btw 9% of 578 is 52.02, so it works

7 0
2 years ago
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A local hamburger shop sold a combined total of hamburgers and cheeseburgers on Thursday. There were fewer cheeseburgers sold th
myrzilka [38]

Answer:

the number of hamburgers sold on Thursday were 325.

Step-by-step explanation:

The total number of hamburger and cheese burger is missing

i will replace it with any figure, you can replace it wit your given data and you will get the solution.

A local hamburger shop sold a combined total of 593 hamburgers and cheeseburgers on Thursday

There were 57 fewer cheeseburgers sold than hamburgers

How many hamburgers were sold on thursday

Let h be the number of hamburgers and c be the number of cheeseburgers.

Using this information we can set up two equation as:

h+c=593\\c=h-57

Now we need to solve these two equations to get the value of number of hamburgers. For that we use substitution method as shown below:

h+h-57=593\\2h-57=593\\2h=650\\h=325

Therefore, the number of hamburgers sold on Thursday were 325.

6 0
3 years ago
I need help with this math homework.. someone please help
tatuchka [14]
A rotation would also give you this transformation.
You could do a 90 degree counter-clockwise or a 270 degree clockwise
5 0
3 years ago
Help please! Calculate the exact value of cos (a-b) given that sin a= 12/13 with pi/2
zloy xaker [14]

Answer:

56/65

Step-by-step explanation:

First, we know that cos(a-b) = cos(a)cos(b) + sin(a)sin(b)

We know what sin(a) and sin(b) are, and to get cos(a), we can take the equation sin²a + cos²a = 1

Thus,

(12/13)² + cos²a = 1

1 - (12/13)² = cos²a

1- 144/169 = cos²a

cos²a = 25/169

cos(a) = 5/13

Similarly,

(3/5)² + cos²b = 1

1 - (3/5)² = cos²b

1 - 9/25 = cos²b

cos²b = 16/25

cos(b) = 4/5

Our answer is

cos(a-b) = cos(a)cos(b) + sin(a)sin(b)

cos(a-b)  = (5/13)(4/5) + (12/13)(3/5)

cos(a-b)  = 20/65 + 36/65

cos(a-b)  = 56/65

4 0
2 years ago
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