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3 years ago

A prediction from a line graph is

Mathematics

2 answers:

melomori [17]3 years ago

8 0

Answer:

an estimate

Step-by-step explanation:

You got this from Odyssey-ware or something because I have the same exact question I don't know if it's right or not and i'm sorry about that but i'm pretty sure this is the right answer.

timurjin [86]3 years ago

5 0

“Line graphs are useful in that they show data variables and trends very clearly and can help to make predictions about the results of data not yet recorded. They can also be used to display several dependent variables against one independent variable.”

“With a line graph, it is fairly easy to make predictions because line graphs show changes over a period of time. You can look at past performance in a line graph and make a prediction about future performance.”

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The line integral of (2x+9z) ds where the curve is given by the parametric equations x=t, y=t^2, z=t^3 for t between 0 and 1. Pl

Naya [18.7K]

Let r = (t,t^2,t^3)

Then r' = (1, 2t, 3t^2)

General Line integral is:
$\int_a^b f(r) |r'| dt$

The limits are 0 to 1
f(r) = 2x + 9z = 2t +9t^3
|r'| is magnitude of derivative vector $\sqrt{(x')^2 + (y')^2 + (z')^2}$

$\int_0^1 (2t+9t^3) \sqrt{1+4t^2 +9t^4} dt$

Fortunately, this simplifies nicely with a 'u' substitution.

Let u = 1+4t^2 +9t^4

du = 8t + 36t^3 dt

$\int_0^1 \frac{2t+9t^3}{8t+36t^3} \sqrt{u} du \\ \\ \int_0^1 \frac{2t+9t^3}{4(2t+9t^3)} \sqrt{u} du \\ \\ \frac{1}{4} \int_0^1 \sqrt{u} du$

After integrating using power rule, replace 'u' with function for 't' and evaluate limits:
$=\frac{1}{4} |_0^1 (\frac{2}{3}) (1+4t^2 +9t^4)^{3/2} \\ \\ =\frac{1}{6} (14^{3/2} - 1)$

7 0

3 years ago

La barbería El Caleño, tiene en promedio 120 clientes a la semana a

Luba_88 [7]

Queremos maximizar el precio de tal forma que los ingresos no disminuyan.

Ese maximo precio es: $14,040.6

Sabemos que actualmente el precio es:

p = $6,000

El número de clientes es:

C = 120

Actualmente los ingresos son el producto de esos dos números, es decir:

ingresos = $6,000*120 = $720,000

Ahora sabemos que por cada incremento de $700 en el precio, el número de clientes decrece en 10.

Entonces podemos escribir el número de clientes como una ecuación lineal.

C(p) = a*p + b

tal que tenemos dos puntos en esa linea:

($6,000, 120)

($6,700, 110)

La pendiente es:

$a = \frac{110 - 120}{\$6,700 - \$6,000} = \frac{-10}{\$ 700}$

Entonces tenemos:

C(p) = (-10/$700)*p + b

Sabemos que:

C($6,000) = 120 = (-10/$700)*$6,000 + b

120 = -85.71 + b

120 + 85.71 = b =

Entonces la ecuación lineal es:

C(p) = (-10/$700)*p + 205.71

Los ingresos serán dados por:

ingresos = C(p)*p = (-10/$700)*p^2 + 205.71*p

Y queremos maximizar p de tal forma que esto sea igual a lo que obtuvimos antes:

(-10/$700)*p^2 + 205.71*p = $720,000

Entonces debemos resolver la ecuación cuadratica:

(-10/$700)*p^2 + 205.71*p - $720,000 = 0.

Las soluciones son dadas por la formula de Bhaskara.

$p = \frac{-205.71 \pm \sqrt{(205.71)^2 - 4*(-10/\$ 700)*\$ 720,000} }{2*(-10/\$ 700)} \\\\p = \frac{-205.71 \pm 195.45}{(-20/\$ 700)}$

La solución de maximo valor es:

p = (-205.71 - 195.45)/(-20/$700) = $14,040.6

Sí quieres aprender más, puedes leer.

brainly.com/question/8926135

7 0

2 years ago

Last year, the volleyball team paid $5 pair for socks and $17 per pair for shorts on a total purchase of $315. This year they sp

vivado [14]

Answer:

Option E is correct.

12 pairs of socks and 15 pairs of shorts did team buy each year.

Step-by-step explanation:

Let the number of pairs of socks be x and the number pairs of shorts be y.

As per the statement:

Last year, the volleyball team paid $5 pair for socks and $17 per pair for shorts on a total purchase of $315.

⇒ $5x+17y = 315$ .....[1]

It is also given that: This year they spent $342 to buy the same number of socks and shorts, because the socks now cost $6 a pair and the shorts cost $18.

⇒ $6x + 18y = 342$ .....[2]

Multiply equation [1] by 6 both sides we get;

$30x+102y = 1890$ .......[3]

Multiply equation [2] by 5 both sides we get;

$30x +90y = 1710$ .....[4]

Subtract equation [4] from [3] we get;

$12y =180$

Divide both sides by 168 we get;

y = 15

Substitute the given values of y =15 in [1] we get;

5x+17(15) = 315

5x + 255 = 315

Subtract 255 from both sides we get;

5x = 60

Divide both sides by 5 we get;

x = 12

Therefore, 12 pairs of socks and 15 pairs of shorts did team buy each year.

3 0

3 years ago

Which statement are true about the expression representing the area of the patio ?

SVETLANKA909090 [29]

Answer:

yes the answer is c

Step-by-step explanation:

8 0

3 years ago

Look at this letter someone sent me

Dimas [21]

Answer:

nice

Step-by-step explanation:

3 0

3 years ago