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jenyasd209 [6]
3 years ago
8

What is the length of a rectangular garden whose perimeter is 32 cm and area 39 cm^2?

Mathematics
2 answers:
ExtremeBDS [4]3 years ago
8 0

39 minicus 32=7

Step-by-step explanation:

39 `IS THE AREAand 32 cm is the perimeter.7 is the length

kherson [118]3 years ago
3 0

Answer:

Length = 13 cm.

Step-by-step explanation:

If the length is L and the width is W we have the system:

2L + 2W = 32

LW = 39

From the first equation:

L + W = 16 and

L = 16 - W

Substitute this in the second equation:

W(16 - W) = 39

16W - W^2 = 39

W^2 - 16W + 39 = 0

(w - 13)(W - 3) = 0

W = 13, 3

As W < L,  W must be 3  because L = 16-13 = 3 does not make sense.

So Length = 16 - 3 = 13.

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<h3>                1)  x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2</h3><h3>                2)   x_1=-\dfrac13\,,\quad x_2=-3    </h3>

Step-by-step explanation:

<h3>1)</h3>

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<h3>2)</h3><h3>3x^2 + 10x=-3\\\\3x^2+10x+3=0\quad\implies\quad a=3\,,\ b =10\,,\ c=3\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-10\pm\sqrt{10^2-4\cdot3\cdot3}}{2\cdot3}= \dfrac{-10\pm\sqrt{100-36}}6\\\\x_1=\dfrac{-10+\sqrt{64}}6=\dfrac{-10+8}6=-\dfrac13\,,\qquad x_2=\dfrac{-10-8}6=-3</h3>
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