find the exact value given that sin A= -4/5 with A in quadrant IV, tan B=7/24 with b in quadrant III, ; cos C= -5/13 with c in q
1 answer:
You might be interested in
The surface area of the triangular prism is 828 in².
Solution:
Let the missing length of the triangle be x.
Using Pythagoras theorem,
In right triangle, square of the hypotenuse is equal to the sum of the squares of other two sides.
Subtract 144 on both sides of the equation.
Taking square root on both sides, we get
x = 9
The missing length of the triangle is 9 in.
Area of the front triangle =
= 54 in²
Area of the back triangle =
= 54 in²
Area of the sloping rectangle = 20 × 9
= 180 in²
Area of the back rectangle = 20 × 12
= 240 in²
Area of the base rectangle = 20 × 15
= 300 in²
Total area = 54 in² + 54 in² + 180 in² + 240 in² + 300 in²
= 828 in²
The surface area of the triangular prism is 828 in².
<h2>Translating Word Equations into Numerical Equations</h2>
To change words into equations, we can recognize keywords that translate into operations and/or numbers:
- <em>quotient</em> = divide
- <em>a number/the number/two numbers</em> = variables
- <em>sum</em> = add
Let the two numbers be <em>a</em> and <em>b</em>.
We're given:
- quotient of <em>a</em> and <em>b</em> is 3
⇒ - sum of <em>a</em> and <em>b</em> is 8
⇒
First, isolate <em>a</em> in the first equation and substitute it in the second equation to solve for <em>b</em>:
Therefore, one of the numbers is 2. Substitute this into one of our equations to solve for <em>a</em>:
Therefore, the other number is 6.
<h2>Answer</h2>The two numbers are 2 and 6.