Answer:
a. 96 square units
Step-by-step explanation:
The figure is a rectangle with width AB = (20-12) = 8 units and height BC = (20-8) = 12 units.
The area of the rectangle is (8 units)×(12 units) = 96 square units.
Karla bought 2 pounds of red beads , 1 3/4 pounds of green beads , and 10 ounces of string at the craft store. How much do Karla
2 answers:
Answer:
Karla's supplies weigh in all 4.375 pounds or 70 ounces.
Step-by-step explanation:
Karla bought red beads = 2 pounds
green beads = pounds or 1.75 pounds
String = 10 ounces or 0.625 pound
1 pound = 16 ounces
First we convert each product's weight in pounds
red beads = 2 pounds
green beads = or 1.75 pounds
string = 10 ounces 10 ÷ 16 = 0.625 pounds
Total = 2 + 1.75 + 0.625 = 4.375 pounds
4.375 × 16 = 70 ounces
Karla's supplies weigh in all 4.375 pounds or 70 ounces.
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Answer:
The probability that a randomly chosen plate contains the number 2222 is 0.000028 approximately.
The probability that a randomly chosen plate contains the sub-string HI is 0.002548 approximately.
Step-by-step explanation:
Consider the provided information.
Illinois license plates used to consist of either three letters followed by three digits or two letters followed by four digits.
Part (A)
Let A is the ways in which plates consist of three letters followed by three digits and B is the ways in which two letters followed by four digits.
Here repetition is allow. The number of alphabets are 26 and the number of distinct digits are 10.
The numbers of ways in which three letters followed by three digits can be chosen is:
The numbers of ways in which two letters followed by four digits can be chosen is:
Hence, the total number of ways are 17576000 + 6760000 = 24336000
Randomly chosen plate contains the number 2222 that means the first two letter can be any alphabets but the rest of the digit should be 2222.
Thus, the total number of ways that a randomly chosen plate contains the number 2222 number are:
The probability that a randomly chosen plate contains the number 2222 is:
Part (B)
The number of ways in which chosen plate contains the sub-string HI:
If three letters followed by three digits plate contains the sub-string HI, then the number of possible ways are:
If two letters followed by four digits plate contains the sub-string HI, then the number of possible ways are:
Thus, the total number of ways that a randomly chosen plate contains the sub-string HI are:
From part (A) we know that the total number of ways to chose a number plate is 24336000.
The probability that a randomly chosen plate contains the sub-string HI is: