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3 years ago

What the answer to this?

Mathematics

1 answer:

adelina 88 [10]3 years ago

6 0

Answer:

C: 650 should be the correct answer

Step-by-step explanation:

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The 50th term of an arithmetic sequence is 86 and the common difference is 2. Find the first three terms of the sequence.

Nesterboy [21]

$a_n=a_{n-1}+d=a_{n-2}+2d=\cdots=a_1+(n-1)d$

which means

$a_{50}=86=a_1+49\times2\implies a_1=-12$

which in turn means the next two terms are $a_2=-10$ and $a_3=-8$ .

6 0

3 years ago

Please help with these three questions and thank you

Advocard [28]

1.A

2.D

3.B

Step-by-step explanation:

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4 years ago

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soldier1979 [14.2K]

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3 years ago

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Nine tiles numbered 1 through 9 are placed in a bag. A tile is randomly drawn and replaced. Then a

barxatty [35]

Answer:

16/81

Step-by-step explanation:

As the tile is taken and then replaced this means that the probability of the second event is not impacted by the probability of the first (they are independent)

As there are 9 tiles and 4 of them are even, the probability that the first tile drawn is even is 4/9.

There are still 9 tiles and still 4 of them are even for the second tile being drawn so this probability is then also 4/9.

If we want to find the probability of both events we should multiply together these two independent probabilities.

So: $\frac{4}{9} *\frac{4}{9} =\frac{16}{81}$

8 0

4 years ago

The dimensions of a rectangular garden were 4m by 5m. Each dimension was increased by the same amount the garden then had an are

pogonyaev

The dimension of new garden is 7 meter by 8 meter

Solution:

The dimensions of a rectangular garden were 4m by 5m

Length = 4 m

Width = 5 m

Each dimension was increased by the same amount the garden then had an area of 56 square meter

Let "x" be the amount of increase

Then,

Length = 4 + x

Width = 5 + x

Also, given that,

New area = 56 square meter

The area of rectangle is given as:

$Area = length \times width$

Substituting the values we get,

$56 = (4+x)(5+x)\\\\56 = 20 + 4x + 5x + x^2\\\\x^2 + 9x + 20 - 56 = 0\\\\x^2 + 9x -36=0$

Let us solve the above equation by quadratic formula

$\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0\\\\x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Using the above formula,

$\text{For } x^2+9x-36 \text{ we get , }$

a = 1 and b = 9 and c = -36

Substituting the values of a = 1 ; b = 9 ; c = -36 in above quadratic formula we get,

$x = \frac{-9\pm \sqrt{9^2-4\cdot \:1\left(-36\right)}}{2\cdot \:1}\\\\x = \frac{-9\pm \sqrt{81+144}}{2}\\\\x = \frac{-9 \pm 15}{2}$

We get two solutions,

$x = \frac{-9+15}{2} \text{ or } x = \frac{-9-15}{2}\\\\x = 3 \text{ or } x = -12$

Since dimension cannot be negative, ignore x = -12

Thus solution is x = 3

Length = 4 + x = 4 + 3 = 7

Width = 5 + x = 5 + 3 = 8

Thus dimension of new garden is 7 meter by 8 meter

5 0

3 years ago