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earnstyle [38]
3 years ago
11

Which two types of potential energies would be types of mechanical energies?

Mathematics
2 answers:
forsale [732]3 years ago
5 0

Answer:

D

Step-by-step explanation:

lisov135 [29]3 years ago
4 0

Answer:

D) elastic and gravitational

Step-by-step explanation:4.elastic and gravitational

Mechanical energy can be either kinetic energy (energy of motion) or potential energy (stored energy of position).

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A survey of 85 families showed that 36 owned at least one DVD player. Find the 99% confidence interval estimate of the true prop
Katyanochek1 [597]

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\hat{p}\pmz_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\\\\=0.42\pm(2.576)\sqrt{\dfrac{0.42(1-0.42)}{85}}\\\\\approx0.42\pm0.053\\\\=(0.42-0.053,\ 0.42+0.053)=(0.367,\ 0.473)

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3 0
3 years ago
Find the value of c so that (x+2) is a factor of the polynomial<br><br> p(x)=3x^4-x^2+cx-2
DedPeter [7]
Using polynomial long division, we get
         
         3x^3+6x^2+11x
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(x+2) | 3x^4-x^2+cx-2
          -(3x^4+6x^3)
          ____________
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If you're wondering how I did the long division, what I essentially did was get the first value (at the start, it was 3x^4) and divided it by the first value of the divisor (which in x+2 was x) to get 3x^3 in our example. I then subtracted the polynomial by the whole divisor multiplied by, for example, 3x^3 and repeated the process.

For this to be a perfect factor, (x+2)*something must be equal to (22+c)x-2. Focusing on how to cancel out the 2, we have to add 2 to it. To add 2 to it, we have to multiply (x+2) by 1. However, there's a catch, which is that we subtract whatever we multiply (x+2) by, so we have to multiply it by -1 instead. We still need to cross out (22+c)x. Multiplying (x+2) by -1, we get
(-x-2) but by subtracting the whole thing from something means that we have to add -(-x-2)=x+2 to something to get 0. x+2-x-2=0, xo (22+c)x-2 must equal -x-2, meaning that (22+c)=-1 and c=-23
4 0
4 years ago
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