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3 years ago

7/7, solve for k, explain too please

Mathematics

1 answer:

ludmilkaskok [199]3 years ago

7 0

Answer:

k = 7.3333333 ...

You can round accordingly of write the fraction form

Step-by-step explanation:

4/k = 6/11

6 ÷ 4 = 1.5

11 ÷ 1.5 = 7.3333333 ... (repeating)

4/7.333 = 6/11

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8 is greater than w, and w is greater than 3

topjm [15]

Answer:

W is either 4, 5, 6, or 7.

Step-by-step explanation:

7 0

3 years ago

Use the factors of the function and the y-intercept to find the standard form of the equation representing Jared’s function. Typ

Georgia [21]

The y-intercept of a function is the point where the graph crosses the $\mathbf{y = x^3 + 2x^2 - 193x - 270 }$

The factors of the Jared's graph are: (x - 10), (x + 3) and (x + 9)
The y-intercept is -13.5
The standard equation of the function is: $\mathbf{y = x^3 + 2x^2 - 193x - 270 }$

(a) The factors

First, we write out the points where the function cross the x-axis.

The points are:

$\mathbf{x = 10}$

$\mathbf{x = -3}$

$\mathbf{x = -9}$

Equate the above points to 0

$\mathbf{x -10 = 0}$

$\mathbf{x +3 = 0}$

$\mathbf{x +9 = 0}$

Hence, the factors are: (x - 10), (x + 3) and (x + 9)

(b) The y-intercept

This is the point where the graph crosses the y-axis.

From the attached graph, the graph crosses the y-axis at -13.5.

Hence, the y-intercept is -13.5

(c) The standard form

In (a), we have:

$\mathbf{x -10 = 0}$

$\mathbf{x +3 = 0}$

$\mathbf{x +9 = 0}$

Multiply the above equations

$\mathbf{(x - 10) \times (x + 3) \times (x + 9) = 0 \times 0 \times 0}$

$\mathbf{(x - 10) \times (x + 3) \times (x + 9) = 0 }$

Expand

$\mathbf{(x - 10) \times (x^2 + 3x + 9x + 27) = 0 }$

$\mathbf{(x - 10) \times (x^2 + 12x + 27) = 0 }$

Expand

$\mathbf{x^3 + 12x^2 + 27x - 10x^2 - 220x - 270 = 0 }$

Collect like terms

$\mathbf{x^3 + 12x^2 - 10x^2+ 27x - 220x - 270 = 0 }$

$\mathbf{x^3 + 2x^2 - 193x - 270 = 0 }$

Replace 0 with y

$\mathbf{y = x^3 + 2x^2 - 193x - 270 }$

Hence, the standard form is: $\mathbf{y = x^3 + 2x^2 - 193x - 270 }$

Read more about graphs and functions at:

brainly.com/question/18806107

3 0

3 years ago

Evaluate M^2 /p^2 for M = 10, N =-5p and P = -2

kondaur [170]

Answer:

The solution of $\bold{\frac{M^{2}}{P^{2}}}$ for M = 10, N = -5P and P = -2 is 25

Solution:

From question, given that the value of M is 10 and N is -5p and P is -2

We have to evaluate the value of $\frac{M^{2}}{P^{2}}$ ,

By substituting the values of M and N, we get

$\frac{M^{2}}{P^{2}} = \frac{10^{2}}{(-2)^{2}}$

Expanding $\bold{10^{2}}$ :

Here 10 is the base value and 2 is the exponent value. So the base term 10 is multiplied by itself two times.

$10^{2} = 10 \times 10 = 100$

Similarly expanding $\bold{(-2)^{2}}$ :

Here -2 is the base term and 2 is the exponent value. So the base term -2 is multiplied by itself two times.

$(-2)^{2} = -2 \times -2 = 4$

So the equation $\frac{M^{2}}{P^{2}} = \frac{10^{2}}{(-2)^{2}}$ becomes,

$\frac{M^{2}}{P^{2}} = \frac{100}{4}$

By dividing 100 by 4 , we get the result as 25

Hence the solution of $\bold{\frac{M^{2}}{P^{2}}}$ when M = 10 and P = -2 is 25

6 0

4 years ago

The standard error of the regression:_________

Lynna [10]

Answer:

the answer is

A. Is based on squared deviations from the regression line.

Step-by-step explanation:

since the numerator of standard error if N, squaring the value cannot give negative value. dependent variable are the squared units

6 0

3 years ago

^^^^^^^^^^^^^*^^^^^^^^^

irina [24]

the answer is c...........

7 0

3 years ago