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Luba_88 [7]
3 years ago
5

The product of two positive consecutive integers is 132. find the integers.

Mathematics
1 answer:
Vanyuwa [196]3 years ago
4 0
X(x+1) = 132
x^2+x = 132
x^2+x-132 = 0

Factoring this gets you

(x+12)(x-11) = 0

x = 11 only because x = -12 is negative and you’re looking for positive integers

x+1
11+1
12

The two integers are 11 and 12
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Answer: x=1

Step-by-step explanation: Look at highlight_red%28+3%2Ax+%29-highlight_red%28+x+%29%2B2=4.

Eliminated similar terms highlight_red%28+3%2Ax+%29,highlight_red%28+-x+%29 replacing them with highlight_green%28+%283-1%29%2Ax+%29

It becomes highlight_green%28+%283-1%29%2Ax+%29%2B2=4.

Look at %28highlight_red%28+3+%29-highlight_red%28+1+%29%29%2Ax%2B2=4.

Added fractions or integers together

It becomes %28highlight_green%28+2+%29%29%2Ax%2B2=4.

Look at highlight_red%28+%28highlight_red%28+2+%29%29%2Ax+%29%2B2=4.

Remove unneeded parentheses around factor highlight_red%28+2+%29

It becomes highlight_green%28+2+%29%2Ax%2B2=4.

Look at 2%2Ax%2B2=highlight_red%28+4+%29.

Moved these terms to the left highlight_green%28+-4+%29

It becomes 2%2Ax%2B2-highlight_green%28+4+%29=0.

Look at 2%2Ax%2Bhighlight_red%28+2+%29-highlight_red%28+4+%29=0.

Added fractions or integers together

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Look at 2%2Ax%2Bhighlight_red%28+-2+%29=0.

Removed extra sign in front of -2

It becomes 2%2Ax-highlight_green%28+2+%29=0.

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It becomes highlight_green%28+0+%29=0.

Result: 0=0

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6 0
3 years ago
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