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Luba_88 [7]
3 years ago
5

The product of two positive consecutive integers is 132. find the integers.

Mathematics
1 answer:
Vanyuwa [196]3 years ago
4 0
X(x+1) = 132
x^2+x = 132
x^2+x-132 = 0

Factoring this gets you

(x+12)(x-11) = 0

x = 11 only because x = -12 is negative and you’re looking for positive integers

x+1
11+1
12

The two integers are 11 and 12
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k0ka [10]

Answer:

y = - 5x - 1

Step-by-step explanation:

The first thing to do (always) is pay attention to x =0. That at least gives you a partial answer. y = y' - 1. when you put 0 in for whatever y' is you get 0. What about the other numbers? How did they come about.

We have another clue. Whenever you put in a positive number for x, you get a negative answer for y. That's interesting. So y' has a minus sign associated with it.

y = -ax - 1    Make a>0 so there is only 1 minus sign. x cannot have an even power, because an even power would make everything positive except the -1.  

So we'll start with y= - ax - 1 We'll also make the assumption that a = 1

y = - x - 1 That won't work. a >1 otherwise x = 2 won't give - 11

y = -ax - 1

let x = 2

let y = - 11 Solve for a

y = - ax - 1

- 11 = -a*-2 - 1       add   1  to both sides

-11 + 1 = - a(-2) - 1 + 1

- 10 = -2a             Divide by - 2

- 10/-2 = -2a/-2

a = 5

Answer: y = - 5x - 1

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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