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Brilliant_brown [7]
3 years ago
15

The value of 32 cos ⁡ 85 ° is ____ a0. Round your answer to the nearest tenth of the number.

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
5 0

Answer:

2.8

Step-by-step explanation:

32cos 85≈2.8

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one container holds a 1 7/8 quarts of water and a second container holds 5 3/4 quarts of water. how many more quarts of water do
dimulka [17.4K]
So lets solve this!

Quarts of water 1st container holds= 17/8

Quarts of water 2nd container holds= 5 3/4

Quarts of water does the second container holds than the first container=?

First of all we need to change 5 3/4 into an improper fraction

5 3/4= 23/4

Secondly, we need to find the LCM of 17/8 and 23/4

LCM:

17/8= 51/24

23/4= 138/24

So now we have got both of the LCM's 

Quarts of second container holds the first container= 23/4 - 138/24=87/24

Your answer is 87/24

Hope this Helps!




8 0
3 years ago
Which of the following represents the area of a rectangle whose length is 3x + 5 and whose width is. x – 2?.
jolli1 [7]
Area of a rectangle is expressed as the product of length and width. 

Area = l x w
Area = (3x+5)(x-2)
Area = 3x² - 6x + 5x - 10
Area = <span> 3x² - x - 10

Therefore, the correct answer is option D.</span>
8 0
2 years ago
Read 2 more answers
2) How many unique triangles can be drawn with side lengths 5 cm, 10 cm, and 14 cm?
iogann1982 [59]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
Armando has collection of 25 coins . Of the 25 coins , 11 are nickles. What percent of the coins are nickles ?
Marysya12 [62]

Answer:

10%

Step-by-step explanation:

3 0
2 years ago
A student multiplies (4+5i) (3-2i) incorrectly and obtains 12-10i what is the students mistakes
Rufina [12.5K]

Answer:

1. In the multiplication of the imaginary parts, the student forgot to square of i. OR

2. The student has only multiplied the real parts and the imaginary parts.

Correct value =22+7i.

Step-by-step explanation:

The given expression is

(4+5i)(3-2i)

A student multiplies (4+5i) (3-2i) incorrectly and obtains 12-10i.

Student's mistake can be either 1 or second:

1. In the multiplication of the imaginary parts, the student forgot to square of i.

2. The student has only multiplied the real parts and the imaginary parts.

(4+5i)(3-2i)=4\times 3+5\times (-2)i=12-10i

Which is not correct. The correct steps are shown below.

Using distributive property, we get

4(3-2i)+5i(3-2i)

4(3)+4(-2i)+5i(3)+5i(-2i)

12-8i+15i-10i^2

12+7i-10(-1)       [\because i^2=-1]

12+7i+10

22+7i

Therefore, the correct value of (4+5i)(3-2i) is 22+7i.

4 0
2 years ago
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