Answer:
about 170
Step-by-step explanation:
i say thi because 360 into 4 quadrants is 90 per qudrant than tge second quadrant is almost full so i put the answer nearly 2 quadrants
Answer:
centre = (2, - 1), radius = 6
Step-by-step explanation:
Rearrange the equation by placing the x and y terms together and adding 31 to both sides
Given
x² + y² - 4x + 2y - 31 = 0, then
x² - 4x + y² + 2y = 31
Use the method of completing the square
add ( half the coefficient of the x/y term )² to both sides
x² + 2(- 2)x + 4 + y² + 2(1)y + 1 = 31 + 4 + 1
(x - 2)² + (y + 1)² = 36
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r the radius
compare to (x - 2)² + (y + 1)² = 36, then
centre = (2, - 1) and r =
= 6
Answer:
She must sell at least 18 necklaces to have a profit of at least 1,650 . In order to pay for her monthly expenses she needs to sell at least 43 necklaces. If she wants to have 1,650 remaining after paying for her monthly expenses she'll have to sell around 61 necklaces.
Answer:
Cosine
Step-by-step explanation:
Cosine = ![\frac{adjacent}{hypothenuse}](https://tex.z-dn.net/?f=%5Cfrac%7Badjacent%7D%7Bhypothenuse%7D)
Cos 70 = ![\frac{x}{8}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B8%7D)
0.633 = ![\frac{x}{8}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B8%7D)
0.633 x 8 =
x 8
5.064 = x
Answer:
<em>Answer:</em> <em>A</em> ![\overline{TM}\cong \overline{OR}](https://tex.z-dn.net/?f=%5Coverline%7BTM%7D%5Ccong%20%5Coverline%7BOR%7D)
Step-by-step explanation:
The HL Theorem states that if the hypotenuse and leg of one right triangle are congruent to the hypotenuse and leg of another right triangle, then the two triangles are congruent.
Triangles TRO and OMT share the hypotenuse, so the first part of the theorem is met.
Both triangles are right because they have an internal angle of 90°, so the second condition is also met.
Since there is no indication of any leg to be congruent to another leg, we need additional information to prove that both triangles are congruent.
One of these two conditions should be met:
Side TM is congruent to side OR, or
Side MO is congruent to side RT.
From the available options, only the first is correct.
Answer: A ![\mathbf{\overline{TM}\cong \overline{OR}}](https://tex.z-dn.net/?f=%5Cmathbf%7B%5Coverline%7BTM%7D%5Ccong%20%5Coverline%7BOR%7D%7D)