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3 years ago

Last week at a gym, 120 people participated in a biking class. The number of people who ran on a treadmill was

Mathematics

1 answer:

DENIUS [597]3 years ago

6 0

Answer:

180 people ran on the treadmill at the gym last week.

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How do you find the = in alterndte exterior angles

Tresset [83]

Answer:

To find alternate exterior angles, look at that outside space for each crossed line, on different sides of the transversal.

Step-by-step explanation:

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Plz Mark Brainliest!

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3 years ago

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Please help asap everything is in the ss

Radda [10]

It would be x ≤ 13.2.

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3 years ago

3(-2p-1)=-6p -3

tamaranim1 [39]

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the answer is 0

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3 years ago

What value represents the horizontal translation from the graph of the parent function f(x) = x2 to the graph of the function

svet-max [94.6K]

F(x)=x^2
g(x)=(x-4)^2+2
In general, for horizontal shift h, and vertical shift k,
g(x)=(x-h)^2+k
by comparison, we have h=+4, k=+2
=>
horizontal translation of +4 (to the right) and vertical translation of +2 (up)

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3 years ago

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How many seconds will light leaving Los Angeles take to reach the following locations (a) San Francisco (about 500km), (b) Londo

kondor19780726 [428]

Answer:

a) It takes 0.0017s for the light to reach San Francisco.

b) It takes 0.033s for the light to reach London.

c) It takes 1.334s for the light to reach Mars.

d) It takes 149.7s for the light to reach Venus.

Step-by-step explanation:

Here we can solve this problem by using this following formula:

$s = \frac{d}{t}$

In which s is the speed(in km/s), d is the distance(in km) and t is the time(in s).

The light speed is 299 792 458 m / s = 299,792.458 km/s, so $s = 299,792.458$

(a) San Francisco (about 500km)

Find t when $d = 500$ . So

$s = \frac{d}{t}$

$299,792.458 = \frac{500}{t}$

$299,792.458t = 500$

$t = \frac{500}{299,792.458}$

$t = 0.0017s$

It takes 0.0017s for the light to reach San Francisco.

b) London(about 10,000km)

Find t when $d = 10,000$ . So

$s = \frac{d}{t}$

$299,792.458 = \frac{10,000}{t}$

$299,792.458t = 10,000$

$t = \frac{10,000}{299,792.458}$

$t = 0.033s$

It takes 0.033s for the light to reach London.

(c) the Moon (400,000km)

Find t when $d = 400,000$ . So

$s = \frac{d}{t}$

$299,792.458 = \frac{400,000}{t}$

$299,792.458t = 400,000$

$t = \frac{400,000}{299,792.458}$

$t = 1.334s$

It takes 1.334s for the light to reach Mars.

(d) Venus (0.3 A.U. from Earth at its closest approach).

Each A.U. has 149,59,7871 km.

So 0.3 A.U. = 0.3*(149,597,871) = 44,879,361.3. This means that $d = 44,879,361.3$ . So:

$s = \frac{d}{t}$

$299,792.458 = \frac{44,879,361.3}{t}$

$299,792.458t = 44,879,361.3$

$t = \frac{44,879,361.3}{299,792.458}$

$t = 149.7s$

It takes 149.7s for the light to reach Venus.

3 0

3 years ago