The computation shows that the placw on the hill where the cannonball land is 3.75m.
<h3>How to illustrate the information?</h3>
To find where on the hill the cannonball lands
So 0.15x = 2 + 0.12x - 0.002x²
Taking the LHS expression to the right and rearranging we have:
-0.002x² + 0.12x -.0.15x + 2 = 0.
So we have -0.002x²- 0.03x + 2 = 0
I'll multiply through by -1 so we have
0.002x² + 0.03x -2 = 0.
This is a quadratic equation with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25.
The second solution y = 0.15 * 25 = 3.75
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Complete question:
The flight of a cannonball toward a hill is described by the parabola y = 2 + 0.12x - 0.002x 2 . the hill slopes upward along a path given by y = 0.15x. where on the hill does the cannonball land?
Answer:
The answer is the option C
The graph in the attached figure
Step-by-step explanation:
Let
x------> the number of notebooks
y-----> the number of tablets
we know that
The inequality that represent the situation is equal to
Using a graphing tool
see the attached figure
The solution is the triangular shaded area
Answer:
2/3
Step-by-step explanation:
Do 1/3 divided by 4/5 first.
So we are going to flip 4/5 to 5/4. The equation is now:
1/4+1/3 times 5/4
Now we are going to do the multiplication since multiply and division is before adding and subtraction.
1/3 times 5/4 = 5/12
Now we have to add 1/4+5/12
With adding ( and subtracting) we have to find the common denominator which is 12
So now we have 3/12 + 5/12 = 8/12 which reduces to 2/3
