<span>i Ace</span>hello :
let : A(-6,6) B(6,-2)
the center is w((-6+6)/2 , (6-2)/2)....(midel <span>[ AB]
w(0 ,2)
the ridus is : r = AB/2
AB = </span>√(-6-6)²+(6+2)² = √(144+64) =<span>√208/2
</span>an equation in <span>standard form equation of the circle :
</span>(x+0)²+(y-2)² = (√208/2)²=208/4 = 52
Answer: 22
Step-by-step explanation:
Since U is the midpoint of P and R, and S is the midpoint of P and Q, SU must be a midsegment.
By the midsegment theorem, SU is 1/2 the value of QR. Therefore QW = SU*2 = 11*2 = 22.
3x + 9 = 90
3x = 90 - 9 = 81
x = 81/3 = 27
x = 27
Answer:
2 and 4
Step-by-step explanation:
This is the only one where the two angles add up to 180 degrees, aka, a straight line.
