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erik [133]
3 years ago
15

Can you please help that will be super kind of u to do that

Mathematics
2 answers:
Mariana [72]3 years ago
7 0

Answer:

B. 18

Step-by-step explanation:

The number of observations here means every time they saw how many pennies someone brought in. So you count up the total number of dots from 0-50 on here, and there are 18.

mote1985 [20]3 years ago
6 0

Answer:

B

Step-by-step explanation:

I think your supposed to just count the dots

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How to answer h/4 ≤ 2/7
Serjik [45]

I feel you, headaches suck.

Your answer would be  h ≤ 8/7

Step  1  :

           2

Simplify   —

           7

Equation at the end of step  1  :

 h    2

 — -  —  ≤ 0

 4    7

Step  2  :

           h

Simplify   —

           4

Equation at the end of step  2  :

 h    2

 — -  —  ≤ 0

 4    7

Step  3  :

Calculating the Least Common Multiple :

3.1    Find the Least Common Multiple

     The left denominator is :       4

     The right denominator is :       7

After calculating the multipliers you get  h ≤ 8/7

Hope this helps!

Please consider Brainliest!

4 0
3 years ago
FIND THE SLOPE of the line that passes through the points (1,-19) and (-2,-7). You do not need to write the whole equation
ra1l [238]

Answer:

Slope is -12

Step-by-step explanation:

change of y/change of x = -12

3 0
3 years ago
Read 2 more answers
What is 12% of 3500?
kakasveta [241]

Answer:

29,166.6667

Step-by-step explanation:Divide 12% which will turn into 0.12 then divide that with 3500.

6 0
3 years ago
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Help plz i give brainliest
Natasha_Volkova [10]

Answer: Hope this helps :)

\frac{1}{5} b^{27}

<h2><u><em>Mark me as Brainliest please</em></u></h2>
6 0
2 years ago
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Para reunir dinero para su gira de estudios , los alumnos de un curso deciden vender números de una rifa que se encuentran numer
QveST [7]

Respuesta:

0.53

Explicación:

Para calcular la posibilidad del evento A: "ganar la rifa comprando todos los números múltiplos de 3 o 5", debemos usar la siguiente fórmula.

P(A) = casos favorables / casos posibles

Evaluemos primero todos los casos que son múltiplos de 3, entre 1 y 100: 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63, 66, 69, 72, 75, 78, 81, 84, 87, 90, 93, 96, 99. En total son 33.

Ahora, evaluemos todos los casos que son múltiplos de 3, entre 1 y 100: 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95, 100. En total son 20.

El número total de casos favorables es 33 + 20 = 53.

El número de casos posibles es el total de números de 1 a 100, es decir 100.

Luego P(A) = 53/100 = 0.53.

7 0
3 years ago
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