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2 years ago

Please help with 14!

Mathematics

1 answer:

pishuonlain [190]2 years ago

4 0

The answer is c because the variable behind the number s are equal

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Which statement is correct when a scatterplot is constructed? A.The independent variable is the input variable and should be rep

spayn [35]

Answer:- A.The independent variable is the input variable and should be represented by the x-axis.

Explanation:-

A. Correct.

B. Not correct.

Reason:- The independent variable is the input variable and should be represented by the x-axis.

C. Not correct.

Reason:- The dependent variable is the output variable and should be represented by y-axis.

D. Not correct.

Reason:-The dependent variable is the output variable and should be represented by y-axis.

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3 years ago

Could u guys please find the area of this shape I am stuck

Alla [95]

Answer: I believe the answer to the question is 208 the way I found this out is that I address the side up and then Then times that by eight and that’s how I got my answer I hope this helps

Step-by-step explanation:

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3 years ago

True or false the square root of 16 is 4 explain why this is true

skad [1K]

true because the square root is a number times itself and 4*4 is 16

4 0

3 years ago

Read 2 more answers

What value of b will cause the system to have an infinite number of solutions?

irga5000 [103]

b must be equal to -6 for infinitely many solutions for system of equations $y = 6x + b$ and $-3 x+\frac{1}{2} y=-3$

Solution:

Need to calculate value of b so that given system of equations have an infinite number of solutions

$\begin{array}{l}{y=6 x+b} \\\\ {-3 x+\frac{1}{2} y=-3}\end{array}$

Let us bring the equations in same form for sake of simplicity in comparison

$\begin{array}{l}{y=6 x+b} \\\\ {\Rightarrow-6 x+y-b=0 \Rightarrow (1)} \\\\ {\Rightarrow-3 x+\frac{1}{2} y=-3} \\\\ {\Rightarrow -6 x+y=-6} \\\\ {\Rightarrow -6 x+y+6=0 \Rightarrow(2)}\end{array}$

Now we have two equations

$\begin{array}{l}{-6 x+y-b=0\Rightarrow(1)} \\\\ {-6 x+y+6=0\Rightarrow(2)}\end{array}$

Let us first see what is requirement for system of equations have an infinite number of solutions

If $a_{1} x+b_{1} y+c_{1}=0$ and $a_{2} x+b_{2} y+c_{2}=0$ are two equation

$\Rightarrow \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}$ then the given system of equation has no infinitely many solutions.

In our case,

$\begin{array}{l}{a_{1}=-6, \mathrm{b}_{1}=1 \text { and } c_{1}=-\mathrm{b}} \\\\ {a_{2}=-6, \mathrm{b}_{2}=1 \text { and } c_{2}=6} \\\\ {\frac{a_{1}}{a_{2}}=\frac{-6}{-6}=1} \\\\ {\frac{b_{1}}{b_{2}}=\frac{1}{1}=1} \\\\ {\frac{c_{1}}{c_{2}}=\frac{-b}{6}}\end{array}$

As for infinitely many solutions $\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}$

$\begin{array}{l}{\Rightarrow 1=1=\frac{-b}{6}} \\\\ {\Rightarrow6=-b} \\\\ {\Rightarrow b=-6}\end{array}$

Hence b must be equal to -6 for infinitely many solutions for system of equations $y = 6x + b$ and $-3 x+\frac{1}{2} y=-3$

8 0

3 years ago

10t+<img src="https://tex.z-dn.net/?f=%5Cgeq" id="TexFormula1" title="\geq" alt="\geq" align="absmiddle" class="latex-formula">1

Umnica [9.8K]

Answer:

The answer is $t\geq 20$ .

Step-by-step explanation:

To solve the inequality, start by solving for the variable $t$ .

To solve for the variable $t$ , subtract $3.5t$ from both sides. The inequality will look like $6.5t\geq 130$ .

Then, divide both sides by 6.5 in order to get the variable $t$ by itself. The inequality answer will look like $t\geq 20$ .

3 0

2 years ago