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2 years ago

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Which of the following relation is a function? A.{(0,2),(3,6),(0,1),(6,3)}B. {(1,2),(6,7),(9,9),(3,7)} C.{(4,5),(1,3),(5,5),(4,0

)} D.{(-2,0),(0,-4),(-2,4),(0,4)}

1 answer:

valkas [14]2 years ago

6 0

Heya user☺☺

Option c is correct

Hope this will help☺☺

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SBC is an isosceles triangle with main vertex S.

stira [4]

Answer + Step-by-step explanation:

1) D be the symmetric of B with respect to C then CD = BC

A the symmetric of C with respect to B then AB = BC

We obtain :

CD = BC

AB = BC

Then AB = CD

2) m∠SBA = 180 - SBC = 180 - SCB = m∠SCD

3) we have :

BA = CD

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Then

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Answer:

Part A

$f(n)=52-12(n-1)$

$f(n)=\left\{\begin{matrix}52\: \:if \: \:n=1 & \\f(n+1)+12& if\: n\geq 2 \end{matrix}\right.$

Part B

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Part C

1/4,3/4,5/4,7/4,9/4

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Part D:

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Step-by-step explanation:

By definition, an Arithmetic Sequence holds the same difference between each following number.

Part A

$(52,40, 28, 16)\\52-40=12\\40-28=12\\28-16=12\\d=12$

<u>Explicit Formula</u>

To write an explicit formula is to write it as function.

$f(n)=52-12(n-1)$

<u>Recursive Formula</u>

To write it as recursive formula, is to write it as recurrence given to some restrictions:

$f(n)=\left\{\begin{matrix}52\: \:if \: \:n=1 & \\f(n+1)+12& if\: n\geq 2 \end{matrix}\right.$

Part B

$(2,4,8,16,32)\: \:$

Geometric Sequence, since 2*2=4 8*2=16 and 16*2=32 and 8+2=10 8+16=24

Part C

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Arithmetic Sequence, difference

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<u>Explicit Formula:</u>

$g(n)=\frac{1}{4}+\frac{2}{4}(n-1)$

<u>Recursive Formula</u>

$g(n)=\left\{\begin{matrix}\frac{1}{4} &if\:n=1 \\ g(n+1)+\frac{2}{4} &if\: n\geq 2\end{matrix}\right.$

Part D

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<u>Explicit formula</u>

$h(n)=1.1+0.4(n-1)\\$

<u>Recursive Formula</u>

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